Answer:
It is calculated by dividing Resistance, R, by Inductive reactance, XL.
Explanation:
Q is called the Q factor of a resonance circuit. In a parallel resonance circuit, it is calculated by finding the ratio of the power stored in the circuit to the power distributed in the circuit. It is a way of measuring the quality of a circuit or how effective the circuit is.
Q factor is the inverse in the resonance series circuit.
Q factor of a resonance parallel circuit,
<h3>
Q = R/XL</h3>
R = Resistance
XL = Inductive reactance
Answer:
Refractive Index = 1.52
Explanation:
As we know speed of light in vaccum is 3 x 10^8 meters per second and distance tavelled by light is 3.97 km or 397000m.
Time taken by light in vaccum = distance / speed = 397000 / 3 x 10^8 = 1.323 x 10^-3 s
Speed of light in liquid = distance / time taken = 261000 / 1.323 x 10^-3 = 197278911 ms^-1 = 1.972 x 10^ 8 ms^-1
According to Snell's law
Refractive index = speed of light in vaccum / speed of light in medium = 3 x 10^8 ms^-1 / 1.972 x 10^8 ms^-1 = 1.52
If the person if slowing down, then this would mean that this would actually be "negative acceleration". Sense this person first did a mile in 10 minutes, and then the next mile that this person did was actually 15 minutes, then this shows you that they actually went a lot slower. And this is why this would be a great example of "negative acceleration".
Answer:
(a) q=3.07 nC
(b) σ=17 nC/m²
Explanation:
Given data
Radius r=0.12m
Potential V=230 V
To find
(a) Charge q
(b) Charge density σ
Solution
For Part (a)
As we know that potential is:
Substitute the given values
For Part (b)
The charge density is given by:
σ=q/(4πr²)
Substitute the given values and value of q to find charge density
So
σ=17 nC/m²
Answer:
Explanation:
Let the initial speed be u . final speed = 0
v² = u² - 2gh
v is final speed , u is initial speed , h is height .
0 = u² - 2g x 134
u² = 2 x 9.8 x 134
u = 51.25 m /s .
