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sineoko [7]
3 years ago
5

How fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j​

Physics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

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Juan compró un carro que dicen que es muy rápido. Cuándo lo probó recorrió una distancia de 4500m en tan solo 5 min. ¿Qué veloci
sweet [91]

Answer:

Don't know sorry..................

4 0
3 years ago
A jet airliner moving initially at 406 mph (with respect to the ground) to the east moves into a region where the wind is blowin
astraxan [27]

Answer:

966 mph

Explanation:

Using as convention:

- East --> positive x-direction

- North --> Positive y-direction

The x- and y- components of the initial velocity of the jet can be written as

v_{1x} = 406 mph\\v_{1y} = 0

While the components of the velocity of the wind are

v_{2x} = (568)(cos 15^{\circ})=548.6 mph\\v_{2y} = (568)(sin 15^{\circ})=147.0 mph

So the components of the resultant velocity of the jet are

v_x = v_{1x}+v_{2x}=406+548.6=954.6 mph\\v_y = v_{1y}+v_{2y}=0+147.0=147.0 mph

And the new speed is the magnitude of the resultant velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(954.6)^2+(147.0)^2}=965.8 mph \sim 966 mph

6 0
3 years ago
What is the mass of something that weighs 300 N on earth
jeka57 [31]

Answer:

30.5810 kg

Explanation:

6 0
3 years ago
A car is traveling at a constant speed on the highway. Its tires have a diameter of 65.0 cm and are rolling without sliding or s
lesya692 [45]

Answer:

Explanation:

The car is rolling without slipping so Vcm= R×ω = 0.325×49 = 16

4 0
3 years ago
Find the frequency if the period is 15 us.
Sav [38]

Answer:

The frequency is 0.667× 10^{6} Hz.

Explanation:

  1. Period is defined as the time taken by any element to attempt one complete oscillatory motion in one second.
  2. Frequency is the number of complete oscillations made in one second.
  • Frequency and period are inversely proportional to each other.
  • In mathematical term: frequency = \frac{1}{period}.
  • As we are given, period = 15×10^{-6} s.
  • We can easily calculate frequency as: f\\= \frac{1}{15. 10^{-6} }
  • So frequency is f= 0.667× 10^{6} Hz.
6 0
3 years ago
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