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sineoko [7]
3 years ago
5

How fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j​

Physics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

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Answer:

5.4 ms⁻¹

Explanation:

Here we have to use conservation of energy. Initially when the stick is held vertical, its center of mass is at some height above the ground, hence the stick has some gravitational potential energy. As the stick is allowed to fall, its rotates about one. gravitational potential energy of the stick gets converted into rotational kinetic energy.

L = length of the meter stick = 1 m

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w = angular speed of the meter stick as it hits the floor

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we know that, linear speed and angular speed are related as

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h = height of center of mass of meter stick above the floor = \frac{L}{2} = \frac{1}{2} = 0.5 m

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For a stick, momentof inertia about one end has the formula as

I = \frac{mL^{2} }{3}

Using conservation of energy

Rotational kinetic energy of the stick = gravitational potential energy

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