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olga_2 [115]
4 years ago
8

Ikg.

Physics
1 answer:
Tcecarenko [31]4 years ago
6 0

Answer:

The mass of G1 at all times during this trial was <u>0.5</u> kg.

The velocity of G1 + G2 after the collision was <u>-1.24</u> m/s.

The momentum of G1 after the collision was <u>-2.10</u> kg · m/s.

Explanation:

i got it right

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Placing the north pole of a magnet near the south pole of another magnet results in:
MakcuM [25]

Answer:

An attractive force between the magnets. A is the correct answer if it was the north pole facing another north pole magnet the answer would have been a repulsive force between the magnets because the north pole of a magnet does not attract instead it separates from each other which is a repulsive force the best answer is A.

Explanation:

the southern pole of a magnet is a positive force while the northern pole of a magnet is negative .

Note: Magnet can attract each other only when they are facing the opposite directions a north pole will attract a south pole; the magnets pull on each other. But the two north poles will push each other away.

8 0
3 years ago
How do you convert 1.3*10^6cal into joules
ehidna [41]

Answer:

5.4×10⁶J

Explanation:

1 cal = 4.184 J

1.3×10⁶ cal × (4.184 J/cal) = 5.4×10⁶J

3 0
3 years ago
Approximating the eye as a single thin lens 2.70 cmcm from the retina, find the focal length of the eye when it is focused on an
Lena [83]

Answer:

0.37 cm

Explanation:

The image is formed on the retina which is at a constant distance of 2.70 cm to the lens. Therefore, image distance = 2.70 cm.

The object is at a distant of 265 cm to the lens of the eye.

From lens formula,

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

where: f is the focal length, u is the object distance and v is the image distance.

Thus, u = 265.00 cm and v = 2.70 cm.

\frac{1}{f} = \frac{1}{265} + \frac{27}{10}

  = \frac{10+7155}{2650}

\frac{1}{f}  = \frac{7165}{2650}

⇒ f = \frac{2650}{7165}

      = 0.37

The focal length of the eye is 0.37 cm.

8 0
3 years ago
Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC.Express your answer in kilojoules
PolarNik [594]
The amount of heat will be equal to Lm.

Where L is the latent heat of fusion and m is mass of the ice.

Latent heat of ice = 80cal/g.

So the amount of heat required here will be 35× 80cal

= 2,800 cal.
6 0
3 years ago
Read 2 more answers
Consider an electron near the Earth's equator. In which direction does it tend to deflect if its velocity is (a) directed downwa
Elenna [48]

The electron near the Earth's equator doesn't deflect if it's velocity is directed downwards.

Assume that north is directed along upwards, south is directed along downwards, east is directed along rightwards, and west is directed along leftwards.

The magnetic force on the charge q, moving with velocity v in the magnetic field B is given by

F=q(→v×→B)=qvBsinθ ..(1)

Here,

θ is the angle between the magnetic field and velocity.

Inside the Earth, the Earth's magnetic field is along northward (upwards), and the velocity is given to be along southwards (downwards) making an angle of 180°. In equation (1) sin180°=0. So, no magnetic force acts on the electron

Therefore,

The electron didn't deflect if it is directed downwards.

To know more about "Magnetic field"

Refer this link:

brainly.com/question/25573309

#SPJ4

4 0
2 years ago
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