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olga_2 [115]
4 years ago
8

Ikg.

Physics
1 answer:
Tcecarenko [31]4 years ago
6 0

Answer:

The mass of G1 at all times during this trial was <u>0.5</u> kg.

The velocity of G1 + G2 after the collision was <u>-1.24</u> m/s.

The momentum of G1 after the collision was <u>-2.10</u> kg · m/s.

Explanation:

i got it right

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A wooden ring whose mean diameter is 15.0 cm is wound with a closely spaced toroidal winding of 555 turns. Compute the magnitude
ruslelena [56]

Answer:

9.916\times 10^{-4}T

Explanation:

Diameter of toroid is 15 cm =0.15 m

So length of the toroid is l=\pi d=3.14\times 0.15=0.471\ m

Number of turns of the toriod is given as 555

Current through the toroid is 0.670 A

Magnetic field B=\mu _0ni=\mu _0\frac{N}{L}i=4\pi \times 10^{-7}\times \frac{555}{0.471}\times 0.670=9.916\times 10^{-4}T

7 0
4 years ago
A 6.5 l sample of nitrogen at 25◦c and 1.5 atm is allowed to expand to 13.0 l. the temperature remains constant. what is the fin
ollegr [7]
Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:
pV=k
which can also be rewritten as
p_1 V_1 = p_2 V_2 (1)
where the labels 1 and 2 mark the initial and final conditions of the gas.

In our problem, p_1 = 1.5 atm, V_1 =6.5 L and V_2 =13.0 L, so the final pressure of the gas can be found by re-arranging eq.(1):
p_2 = p_1  \frac{V_1}{V_2}= (1.5 atm) \frac{6.5 L}{13.0 L}=0.75 atm

Therefore the correct answer is
<span>1. 0.75 atm</span> 
8 0
3 years ago
Excellent human jumpers can leap straight up to a height of
Firlakuza [10]

For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.  

We can calculate the initial speed to reach 110 cm of height with the following equation:

v_{f}^{2} = v_{i}^{2} - 2gh

Where:

v_{f}: is the final speed = 0 (at the maximum height of 110 cm)

v_{i}: is the initial speed =?

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 110 cm = 1.10 m

Hence, the <u>initial velocity</u> is:

v_{i} = \sqrt{v_{f}^{2} + 2gh} = \sqrt{2*9.81 m/s^{2}*1.10 m} = 4.65 m/s

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.

You can see another example here: brainly.com/question/13359681?referrer=searchResults

I hope it helps you!

4 0
3 years ago
Explain why it is easier to climb a mountain on a zigzag path rather than one straight up the side.
GaryK [48]
Although a zig zag pattern going up a mountain means you walk further, the incline of the slope is a lot less so you don't have to work as hard.
8 0
3 years ago
a fan is rotating clockwise and its acceleration has a positive sign. is the angular velocity of the fan speeding up, slowing do
balu736 [363]

Answer:

The angular velocity is slowing down.

Explanation:

  • By convention, if a rigid body is rotating clockwise, the angular velocity is negative.
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5 0
3 years ago
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