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yulyashka [42]
3 years ago
9

Wesley pushed a tennis ball down a long driveway in 2.5s. The ball traveled at a constant acceleration of 1.8 m/s2 down the slop

e and was traveling at a
velocity of 7.6 m/s by the time it reached the street at the end of the driveway. How fast was the ball going when it left Wesley's hand?
A. 14.5 m/s
B. 3.1 m/s
C. -0.5 m/s
D. 12.1 m/s
Physics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

14.5m/s

Explanation:you had to divide 2.5s divide that by 1.8

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Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
pochemuha

Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

Area of the rectangle = 3.5504mm²

The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

Area of the rectangle = 3.6mm² (to 2sf)

For statement B;

Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.

Area of the rectangle = 2.536mm * 1.41mm

Area of the rectangle = 3.57576mm²

Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.

Area of the rectangle = 3.58mm² (to 3sf)

Based on the conversion, it can be seen that 3.6mm²  is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.

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Question 8 of 25
Dima020 [189]

Answer:

B.

Explanation:

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When a body is moving with a uniform velocity, the acceleration is ___?
denis23 [38]
<span>According to the formula : 
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Answer:

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Explanation:

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E=jP where P is resistivity and j is current density

But the current density is given as

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Substituting this into the first equation then E=P\times \frac {I}{\pi r^{2}}

Given diameter of 0.259 cm= 0.00259 m and the radius will be half of it which is 0.001295 m

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