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SVETLANKA909090 [29]
3 years ago
11

Which conclusion was a direct result of the gold foil experiment?

Chemistry
1 answer:
kari74 [83]3 years ago
3 0
They determined that (1) An atom is mostly empty space with a sense, positively charged nucleus, because most particles passed straight through the gold foil, but occasionally they would deflect, sometimes by a very large margin
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Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0
3 years ago
What must be true for a spontaneous reaction in an electrochemical cell? The overall cell potential must be positive. The overal
yanalaym [24]

Answer:

The overall cell potential must be positive.

Explanation:

What must be true for a spontaneous reaction in an electrochemical cell?

  • The overall cell potential must be positive. YES. This is by convention.
  • The overall cell potential must be negative. NO. By convention, a negative cell potential means the cell is not spontaneous.
  • The cathode’s standard reduction potential must be positive. NO. It only has to be higher than the anode's standard reduction potential.
  • The cathode’s standard reduction potential must be negative. NO. It only has to be higher than the anode's standard reduction potential.
7 0
3 years ago
Which is not true regarding reaction rates? (2 points)
PtichkaEL [24]

Let us consider each statement one by one

a) Catalysts are the substance which alter the reaction pathway where activation energy of reaction is less that the un catalyzed reaction. They are not used up in the reaction . the catalyst is restored in the reaction.

b) As mentioned above, the catalyst speed up reaction by lowering the activation energy

c) During a reaction the reactants are consumed up and products are formed. so there is a decrease in concentration of reactant.

Thus all the above statements are true.

D) the rate of decrease in concentration of reactants depends upon the coefficient of reactant in balanced chemical reaction.

For example

H_{2} (g)  + \frac{1}{2} O_{2} (g) -->    H_{2}O(g)

Here the rate of decrease in concentration of hydrogen will be double the rate of decrease in concentration of oxygen.

5 0
3 years ago
Please help i will mark brainliest
Ostrovityanka [42]

Answer:

search it up

Explanation:

khan academy hope this helps

4 0
3 years ago
Which particle has the least mass alpha,neutron,betas particle,or proton
Cerrena [4.2K]
Alpha particle: 3.7273
neutron: 1.0087
beta particle: 0.000544
proton: 1.0073

<span>The beta particle weighs the least in comparison to the others </span>
5 0
4 years ago
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