I think it's reactivity. but i'm not sure.
The mixture contains 62 % one isomer and 38 % the enantiomer.
Let’s say that the mixture contains 62 % of the (<em>R</em>)-isomer.
Then % (<em>S</em>) = 100 % -62 % = 38 %
ee = % (<em>R</em>) - % (<em>S</em>) = 62 % -38 % = 24 %
The hydrogen Ion concentration of solution B is
1.0 x 10^-5 or 0.000 010 M
You can see that this will be proportional to the amount of B's PH compared to A's
hope this helps