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Vilka [71]
3 years ago
14

In the 4th paragraph, it says disturbances like "accelerated erosion, or change in vegetation cover" tend to persist and grow ov

er time, rather than a return to the pre-disturbance condition. Why do you think this is the case?
Chemistry
1 answer:
deff fn [24]3 years ago
7 0

Answer:

Erosion is the washing away of the uppermost part of the earth crust. Once erosion starts it only gets worse because, erosion wash away further soil, causing the eroding channel to futher expand, increasing the erosion.

Lack of vegetative cover allows erosion which washes away soil nutrients, further worsening the soil against soil vegetative cover.

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If you were to react 4.3 miles of magnesium phosphide how many moles of potassium would you need?
bixtya [17]

Answer:

25.8

Explanation:

Let's write the reaction between magnesium-phosphide and potassium:

Mg3P2 + K = Mg + K3P

And now let's balance this equation:

Mg3P2+6K=3Mg+2K3P

We see that the ratio of magnesium-phosphide and potassium is 1:6, which means that for every mole of magnesium-phosphide there need to be 6 moles of potassium.

Since we have 4.3 moles of Mg3P2, there need to be 6 • 4.3 = 25.8 moles of potassium.

5 0
3 years ago
Ill give the brainliest answer to whoever helps me with this equation
vampirchik [111]

Answer: The percent yield for the NaBr is, 86.7 %

Explanation : Given,

Moles of FeBr_3 = 2.36 mol

Moles of NaBr = 6.14 mol

First we have to calculate the moles of NaBr

The balanced chemical equation is:

2FeBr_3+3Na_2S\rightarrow Fe_2S_3+6NaBr

From the reaction, we conclude that

As, 2 moles of FeBr_3 react to give 6 moles of NaBr

So, 2.36 moles of FeBr_3 react to give \frac{6}{2}\times 2.36=7.08 mole of NaBr

Now we have to calculate the percent yield for the NaBr.

\text{Percent yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield = 6.14 moles

Theoretical yield = 7.08 moles

Now put all the given values in this formula, we get:

\text{Percent yield}=\frac{6.14mol}{7.08mol}\times 100=86.7\%

Therefore, the percent yield for the NaBr is, 86.7 %

6 0
3 years ago
What volume does 76 g of fluorine gas occupy at stp?
solong [7]
<span>2 * 22.4 = 44.8 liters (if using pre 1982 standard) 2 * 22.7 = 45.4 liters (if using 1982 and later standard) First, let's determine how many moles of F2 we have. Atomic weight fluorine = 18.998403 Molar mass F2 = 2 * 18.998403 = 37.996806 g/mol Moles F2 = 76 g / 37.996806 g/mol = 2.000168119 mol Now we have a minor problem. What definition of STP are you using? Up until 1982, STP was defined as 0°C and 1 atmosphere (101.325 kPa) From 1982 and later, STP was defined as 0°C and 100 kPa Because of the difference in pressure between the two different definitions of STP, the molar volume of a gas is 22.414 liter/mol using the pre-1982 definition and 22.711 liter/mol using the 1982 and later definition. So you get to choose which of the following 2 answers. 2 * 22.4 = 44.8 liters (if using pre 1982 standard) 2 * 22.7 = 45.4 liters (if using 1982 and later standard) Unfortunately there's still a large number of text books in use using the standard that should have been obsolete 35 years ago.</span>
4 0
3 years ago
2.What two factors must be held constant for density to be a constant ratio?
irina1246 [14]

Answer:

Temperature and Pressure

Explanation:

Temperature and pressure cause change in volume.

So any change in volume will alter the ratio of density as given by equation of density.

Density = mass/ volume

Change in volume will alter the ratio.

Kindly mark it branliest if the answer is little bit satisfying.

6 0
3 years ago
Read 2 more answers
How do water particles move in a wave? A. They move forward with the wave. B. They move in a circular motion. C. They move up an
Olin [163]
Sorry if I'm wrong but I think that it is B. 
4 0
3 years ago
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