Answer:
2C2H6(g) + 7O2(g) ==> 4CO2(g) + 6H2O(g)
One way to find the limiting reactant is to divide the moles of reactant by the corresponding coefficient in the balanced equation and whichever is less is limiting.
For C2H6 we have 2 moles / 2 = 1
For O2 we have 8 moles / 7 = 1.14
Explanation:
If a reaction mixture contains 8 moles of O2(g) with 2 moles of C2H6(g),which reactant is the limiting reactqnt and what is the mass (in grams) remaining of the reactant in excess?
Zero degree celcius = 273.15 degree kelvin
Simply, to get the value of 45.1 degree celcius in kelvin, we will add 273.15 to the given value (45.1).
Degree in kelvin = 45.1 + 273.15 = 318.25 degree kelvin
Approximating to the nearest tenth, the value will be 318.3 degree kelvin
By hot springs, fumaroles and geysers.
Answer:
The maximum potential energy of the child will be maximum at the two end points.
The maximum kinetic energy of the <em>child </em>occurs at the lowest point of the swing.
The potential energy of the child depends on the displacement of the child.
P.E = mgh
The maximum height attained occurs at the two end points of her swing motion.
Thus, the maximum potential energy of the child will be maximum at the two end points.
The kinetic energy of the child depends on the velocity of the child
K.E = ¹/₂mv²
The maximum velocity of the swing occurs at the lowest point of the swing.
Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.
Hope this helps!
