Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

CuO = 79.545 g/mol

H2O = 18.015 g/mol

Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

3.327 g CuO__________ x =3.327*18.015 /79.545 g water

x= 0.7535 g water

3 0

3 years ago

What is △n for the following equation in relating Kc to Kp?

Nimfa-mama [501]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

$K_p= K_c\times (RT)^{\Delta n}$

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant , 0.082057 L atm.mol⁻¹K⁻¹

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

$2Na_{(s)}+2H_2O_{(l)}\rightleftharpoons 2NaOH_{(aq)}+2H_2_{(g)}$

<u>Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants) = (2+1)-(2+2) = -1 </u>

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7 0

3 years ago

Interstellar space has an average temperature of about 10 K , and an average density of hydrogen atoms of about one hydrogen ato

Bas_tet [7]

Answer:

$2.2508\times 10^{19} m$ meter the mean free path of hydrogen atoms in interstellar space.Explanation:

The mean free path equation is given as:

$\lambda =\frac{1}{\sqrt{2}\pi d^2 n}$

Where"

d = diameter of hydrogen atom in meters

n = number of molecules per unit volume

We are given: d = 100 pm = $100\times 10^{-12}= 10^{-10} m$

$n = 1 m^{-3}$

$\lambda =\frac{1}{\sqrt{2}\pi (10^{-10} m)^2\times 1 m^{-3}}$

$\lambda =2.2508\times 10^{19} m$

$2.2508\times 10^{19} m$ meter the mean free path of hydrogen atoms in interstellar space.

7 0

3 years ago