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BabaBlast [244]
3 years ago
5

A student measures the S2- concentration in a saturated aqueous solution of iron(II) sulfide to be 2.29×10-9 M. Based on her dat

a, the solubility product constant for iron(II) sulfide is
Chemistry
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

Ksp FeS = 5.2441 E-18

Explanation:

  • FeS ↔ Fe2+  + S2-

         S          S           S

∴ Ksp = [Fe2+]*[S2-].....solubility product constant

∴ [S2-] = 2.29 E-9 M = S

⇒ Ksp = (S)(S) = S²

⇒ Ksp = (2.29 E-9)²

⇒ Ksp = 5.2441 E-18

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