Which type of radioactive decay can pass through the body?
1 answer:
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Answer:
0.0002 M
Explanation:
<em>The molarity of the HCl required would be 0.0002 M.</em>
First, let us consider the balanced equation of the reaction:
<em>Stoichiometrically, 1 mole of </em><em> reacts with 2 moles of </em>
<em> for a complete neutralization reaction.</em>
Recall that: mole =
Mole of 0.550 g sodium oxalate = 0.550/134 = 0.0041 mole
<em>If 1 mole </em><em> requires 2 moles HCl, then 0.0041 mole will require</em>:
0.0041 x 2 = 0.0082 mole HCl
Volume of the HCl = 40.95 L
Molarity = mole/volume
Hence, molarity of the HCl = 0.0082/40.95 = 0.0002 M