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Setler [38]
3 years ago
15

g What is the molarity of hydrochloric acid if 40.95 mL of HCl is required to neutralize 0.550 g of sodium oxalate, Na2C2O4

Chemistry
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

0.0002 M

Explanation:

<em>The molarity of the HCl required would be 0.0002 M.</em>

First, let us consider the balanced equation of the reaction:

Na_2C_2O_4 + 2HCl = 2NaCl + H_2 + 2CO_2

<em>Stoichiometrically, 1 mole of </em>Na_2C_2O_4<em> reacts with 2 moles of </em>HCl<em> for a complete neutralization reaction.</em>

Recall that: mole = \frac{mass}{molar mass}

Mole of 0.550 g sodium oxalate = 0.550/134 = 0.0041 mole

<em>If 1 mole </em>Na_2C_2O_4<em> requires 2 moles HCl, then 0.0041 mole will require</em>:

    0.0041 x 2 = 0.0082 mole HCl

Volume of the HCl = 40.95 L

Molarity = mole/volume

Hence, molarity of the HCl = 0.0082/40.95 = 0.0002 M

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