Answer:
Explanation:
Expression for capillary rise is as follows
h = 2T / ρ g r where T is surface tension , ρ is density of liquid and r is radius of capillary tube.
T = .032 J m⁻²
ρ = .71 g / cm³
= 7100 kg / m³
r = .1 x 10⁻³ m = 10⁻⁴ m
h = 2 x .032 / (7100 x 9.8 x 10⁻⁴ )
h = .0092 m
= 9.2 mm .
Answer:
Explanation:
We have the reactions:
A: 
B: 
Our <u>target reaction</u> is:
We have 
as a reactive in the target reaction and is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.
A: 
Then if we add reactions A and B we can obtain the target reaction, so:
A:
B: 
For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.
A mole of any gas occupied 22.4 L at STP. So, the number of moles of nitrogen gas at STP in 846 L would be 846/22.4 = 37.8 moles of nitrogen gas.
Alternatively, you can go the long route and use the ideal gas law to solve for the number of moles of nitrogen given STP conditions (273 K and 1.00 atm). From PV = nRT, we can get n = PV/RT. Plugging in our values, and using 0.08206 L•atm/K•mol as our gas constant, R, we get n = (1.00)(846)/(0.08206)(273) = 37.8 moles, which confirms our answer.
Answer:
can we see the type that is shown?
Answer:
2 grams.
Explanation:
H2 + O2 ---> H2O2
Using molar masses:
2*1 g hydrogen reacts with 2*16 g oxygen.
so 2g H2 reacts with 32 g O2.
