A 40.0 L balloon is filled with air at sea level (1 atm @ 25 oC). It is then tied to a rock and thrown into a cold lake and it s
inks to the bottom! When it reaches the bottom of the lake the temperature is 4.0 oC and the pressure has increased to 11 atm. What will the new volume be? A. 0.295 L
B. 3.38 L
C. 3.91 L
D. 187.6 L
To solve this question you need to calculate the number of the gas molecule. The calculation would be: PV=nRT n=PV/RT n= 1 atm * 40 L/ (0.082 L atm mol-1K-<span>1 * 298.15K) </span>n= 1.636 moles
The volume at bottom of the lake would be: PV=nRT V= nRT/P V= (1.636 mol * 277.15K* 0.082 L atm mol-1K-1 )/ 11 atm= <span>3.38 L</span>