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Gwar [14]
3 years ago
15

Using the periodic table, choose the more reactive non-metal. At or Br

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
3 0
Bromine (Br) it's closer to the top right corner, which are the most reactive elements on the right side of the periodic table.
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What happens when acetylene reacts with silver powder?​
horrorfan [7]
It dissolves I think I know I am expert and. Ute
6 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
4 years ago
To use the gas law constant R=0.0821 the unit for temp should be kelvin and the unit for pressure should be atmospheres True or
hoa [83]

It is crucial to match your units of Pressure, Volume, number of mole, and Temperature with the units of R. If you use the first value of R, which is 0.082057 L atm mol-1K-1, your unit for pressure must be atm, for volume must be liter, for temperature must be Kelvin.

7 0
4 years ago
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What must happen for an ionic bond to be created between two elements?
dezoksy [38]

Answer:

they must be heated

Explanation:

3 0
4 years ago
A compound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% C, 3.0% H, 16.0% O and 57.0%F. What is the mol
ch4aika [34]

If I made no mistake in calculation, the given answer must be correct...(tried my best)



elements   :                        carbon     hydrogen    oxygen       Fluorine

 composition [C]                     24             3                16                57

M r                                          12             1                16                19

(divide C by Mr)                       2               3                 1                  3


(Divide by smallest value)       2                3                  1                  3

(smallest value = 1...so all value remained constant)

Empirical formula : C2H3OF3


if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula:  [= 100]


Them molecular formula = empirical formula

    
7 0
4 years ago
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