Molar solubility is the number of moles that are dissolved in 1 L solution. when BaF₂ dissolves it dissociates into the following ions BaF₂ --> Ba²⁺ + 2F⁻ if the molar solubility of BaF₂ is X, then molar solubility of Ba²⁺ is X and F⁻ is 2x then the formula for the solubility product constant -ksp is; ksp = [Ba²⁺][F⁻]² ksp = X * (2X)² ksp = 4X³ since ksp = 1.7 x 10⁻⁶ 4X³ = 1.7 x 10⁻⁶ X = 0.0075 M molar solubility of BaF₂ is 0.0075 M