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Darina [25.2K]
4 years ago
6

Planet z is 5000 km in diameter. the free-fall acceleration on planet z is 7.0 m/s2. part a what is the mass of planet z? expres

s your answer using two significant figures. m = kg submitmy answersgive up part b what is the free-fall acceleration 9000 km above planet z's north pole? express your answer using two significant figures.
Physics
1 answer:
timama [110]4 years ago
3 0
(a) g = Gm/r^2
where G=6.67 * 10^-11 Nm^2/kg^2,
m is the mass of the planet,
r is the radius of the planet. 
7.0 = (6.67 * 10^-11)/(2500^2) * m
m= (25000000^2 * 9.0)/(6.67 * 10^-11) 
m = 8.4333 x 10^24 kg
(b) g=Gm/r^2. This time, the radius is 2500+10000 = 12500km g = (6.67 * 10^-11 * 8.43333*10^18)/(12500^2) 

g = 3.6 m/s^2 
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Humans can hear frequencies as low as 21 Hz. If sound is measured during 3 seconds how many wavelengths pass?
SVEN [57.7K]
63 hertz.
This is because a hertz is how often a sound wave repeats.
8 0
4 years ago
If the atmospheric pressure in a tank is 23 atmospheres at an altitude of 1,000 feet, the air temperature in the tank is 700F, a
liraira [26]

Answer:

W = 289.70 kg

Explanation:

Given data:

Pressure in tank = 23 atm

Altitude 1000 ft

Air temperature  in tank T = 700 F

Volume of tank = 800 ft^3 = 22.654 m^3

from ideal gas equation we have

PV =n RT

Therefore number of mole inside the tank is

\frac{1}{n} = \frac{RT}{PV}

              = \frac{8.206\times 10^{-5}} 644.261}{23\times 22.654}

               = 1.02\times 10^{-4}

               n = 10^4 mole

we know that 1 mole of air weight is 28.97 g

therefore, tank air weight is W = 10^4\times 28.91 g = 289700 g

               W = 289.70 kg

6 0
3 years ago
A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0
viktelen [127]

Hi there!

Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.

We also know there was work done on the ball by air resistance that decreased the ball's total energy.

Let's do a summation using the equations:
KE = \frac{1}{2}mv^2 \\\\PE = mgh

Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)

E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)

Our final energy, since we set the zero-line to be at H2, is just kinetic energy.

E_f = \frac{1}{2}mv_f^2

And:
W_A = E_i - E_f

The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.

Therefore:
W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) -  \frac{1}{2}mv_f^2

Solving for the work done by air resistance:
W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) -  \frac{1}{2}(.450)(19.89^2)

W_A = \boxed{42.552 J}

8 0
2 years ago
Explain why it is important to stop playing a sport after sustaining an injury even if the pain seems to go away.
juin [17]

Answer:

Continuing to play if you have an injury can make that injury worse. A small stress fracture that might have healed quickly can grow into a more serious, more painful fracture that will take longer to heal. Returning to play too soon after a concussion increases your risk of serious brain injury.

Explanation: Trust me it right bro

6 0
2 years ago
Read 2 more answers
two negative charges that are both -3.0 C push each other apart with a force of 19.2 N how far apart are the charges
Hoochie [10]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
where k_e =8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant and r is the distance between the two charges.

If we use F=19.2 N and q1=q2=-3.0 C, we can find the value of r, the  distance between the two charges by re-arranging the previous formula:
r= \sqrt{k_e \frac{q_1 q_2}{F} }= \sqrt{ 8.99 \cdot 10^9 N m^2 C^{-2} \frac{(-3.0C)^2}{19.2 N} } =6.49 \cdot 10^4 m=64.9 km
5 0
4 years ago
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