If the atmospheric pressure in a tank is 23 atmospheres at an altitude of 1,000 feet, the air temperature in the tank is 700F, a
1 answer:
Answer:
W = 289.70 kg
Explanation:
Given data:
Pressure in tank = 23 atm
Altitude 1000 ft
Air temperature in tank T = 700 F
Volume of tank = 800 ft^3 = 22.654 m^3
from ideal gas equation we have
PV =n RT
Therefore number of mole inside the tank is
we know that 1 mole of air weight is 28.97 g
therefore, tank air weight is
W = 289.70 kg
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