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Andrews [41]
3 years ago
8

if 15 mol C is mixed with 10 mol O2 which reactant is the limiting reactant? Which reactant would be the excess reactant?

Chemistry
1 answer:
ioda3 years ago
6 0

Answer:

C is the excess reactant.

Explanation:

Reaction is C + O2 --> CO2

1mol of C required to react with 1mol O2

Therefore 15 - 10 = 5moles of C will be in excess

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PLEASE HELP!
WINSTONCH [101]
I think the answer is a i hope it helps
5 0
3 years ago
Read 2 more answers
*
NISA [10]

Answer:

B: +3

Explanation:

If Gallium loses 3 electrons, it will become an ion.

The ion will be positively charged because in this new ion, the number of electrons is lesser than the number of protons. The charge difference will impart a positive net charge on the ion.

  • In a neutral atom, the number of electrons and protons are the same.
  • For positively charged ions, the number of protons is greater than the electrons

If Gallium the loss of 3 electrons offsets the charge balance in the chemical specie. Thus, the ion will have a net +3 charge.

3 0
2 years ago
Which type of equilibrium exists in a sealed flask containing Br2(ℓ) and Br2(g) at 298 K and 1.0 atm?(1) static phase equilibriu
marishachu [46]
The correct answer is 3.

A dynamic phase equilibrium is when a reversible reaction no longer changes its ratio of reactants to products. However, substances continue to move between the chemicals at an equal rate, which means the net change is 0. This is known as a steady state.
8 0
3 years ago
Hydrogen and nitrogen react to form ammonia according to the reaction, 3 H2 + N2 â> 2 NH3. If 4.0 moles of H2 with 2.0 moles
Debora [2.8K]

Answer:

d) 2.7 mol

Explanation:

  • 3 H2 + N2 → 2 NH3

limit reagent is H2:

∴ Mw H2 = 2.016 g/mol

∴ Mw N2 = 28.0134 g/mol

⇒ moles NH3 = (4.0 moles H2)×(2 mol NH3/3mol H2)

⇒ moles NH3 = 2.666 mol

⇒ moles NH3 ≅ 2.7 mol

5 0
3 years ago
The cells of a tomato contain mostly an aqueous solution of sugar and other substances. If a typical tomato freezes at -2.5 °C,
DIA [1.3K]

Answer:

1.35 m

Explanation:

We can solve this problem by using the <em>freezing point depression formula</em>:

  • ΔT = Kf * m * i

Where:

  • ΔT is the temperature difference between the freezing point of the pure solvent (water) and the solution. In this case it is (<em>0 °C - -2.5 °C = 2.5 °C</em>).
  • Kf is the cryoscopic constant, <em>for water it is 1.853  °C*kg/mol.</em>
  • m is the molality.
  • i is the van't Hoff factor, <em>as sugar does not dissociate in water, it has a value of 1</em>.

We <u>input the data</u>:

  • 2.5 °C = 1.853 °C*kg/mol * m * 1

And <u>solve for m</u>:

  • m = 1.35 m
6 0
3 years ago
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