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Veronika [31]
3 years ago
9

What is the beta decay of uranium-237

Chemistry
1 answer:
Airida [17]3 years ago
3 0
During a phenomenon called beta decay the neutron of the isotope uranium 237 emits/releases an electron causing an increase of atomic number. With the reference of a periodic table the "new" element is Neptunium or Np-237. 
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12.<br> An object with a mass of 3 kg has a momentum of 75 kg•m/s. What is the velocity?
marissa [1.9K]

Answer:

the velocity is 25 m/s

Explanation:

The computation of the velocity is shown below:

As we know that

Magnitude of Momentum = (mass) × (speed)

75 kg. m/s = 3 kg × speed

So, the speed is

= 75 ÷ 3

= 25 m/s

hence, the velocity is 25 m/s

3 0
3 years ago
How do i balance the first chemical reaction above?? plz plz help
soldier1979 [14.2K]

Answer:

2K +F₂→ 2KF

Explanation:

When we balance an equation, we are trying to ensure that the number of atoms of each element is the same on both sides of the arrow.

On the left side of the arrow, there is 1 K atom and 2 F atoms. On the right, there is 1 K and 1 F atom.

Since the number of K atoms is currently balanced, balance the number of F atoms.

K +F₂→ 2KF

Now, that the number of F atoms is balanced on both sides, check if the number of K atoms are balanced.

<u>Left</u>

K atoms: 1

F atoms: 2

<u>Right</u>

K atoms: 2

F atoms: 2

The number of K atoms is not balanced.

2K +F₂→ 2KF

<u>Left</u>

K atoms: 2

F atoms: 2

<u>Right</u>

K atoms: 2

F atoms: 2

The equation is now balanced.

4 0
3 years ago
What are the major sources of crude oil<br>​
timurjin [86]

Explanation:

Crude oil is a naturally occurring fossil fuel - meaning it comes from the remains of dead organisms.

Crude oil is made up of a mixture of hydrocarbons - hydrogen and carbon atoms.

It exists in liquid form in underground reservoirs in the tiny spaces within sedimentary rocks. Or it can be found near the surface in oil sands.

It is often found alongside natural gas and saline water.

Crude oil is often interchangeably referred to as petroleum. This is because petroleum includes both the unrefined crude oil as well as refined petroleum products.

It is non-renewable - once it’s gone it’s gone and cannot be easily replaced.

5 0
3 years ago
Which separation techniques will you apply for the separation of the following? a) oil from water b) kerosene and petrol c) salt
REY [17]

Answer:

A) Separating funnel method

B) Simple Distillation

C) Evaporation

D) Sublimation

E) It is based on the principle of separation whereby even though two substances are dissolved in the same solvent, their respective solubilities could be different. Thus, the component that has more solubility will rise fastest and will therefore get separated from the mixture.

Explanation:

A)

B) Kerosene and petrol are both miscible liquids and the difference in their boiling point temperature is not more than 25°C. Thus, we make use of Simple distillation.

C) Can be separated by evaporation where the water is boiled and it evaporates and leaves the salt behind

D) To separate camphor from salt, we use sublimation so the camphor can change directly from solid to the gas state without passing through the liquid state.

E) Chromatography is used to separate components of a mixture.

It is based on the principle of separation whereby even though two substances are dissolved in the same solvent, their respective solubilities could be different. Thus, the component that has more solubility will rise fastest and will therefore get separated from the mixture.

7 0
3 years ago
In an electrically heated boiler, water is boiled at 140°C by a 90 cm long, 8 mm diameter horizontal heating element immersed in
RideAnS [48]

Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

                       = 250 kg  

Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

                           = 133.3 \times 10^{3} kJ

All this heat was supplied in 60 min = 60(min)  × 60(sec/min) = 3600 sec

Therefore, heat supplied per unit time = Heat required/time = \frac{133.3 \times 10^{3}kJ}{3600 s} = 37 kJ/s or kW

The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

4 0
3 years ago
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