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Irina18 [472]
2 years ago
13

8. If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A?

Chemistry
1 answer:
lakkis [162]2 years ago
6 0

We have that you can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water

From the question we are told

If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A

Generally the equation for the  Concentration  Volume relationship is mathematically given as

C1V1=C2V2\\\\Where\\\\C1=10X\\\\C2=1X buffer A\\\\V2=450ml \\\\Therefore\\\\V1=\frac{450*1}{10}\\\\V1=45ml

Therefore

You can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water

For more information on this visit

brainly.com/question/17756498

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CHEMISTRY HELP<br> Once the following equation is balanced, what is the correct coefficient for Z₂?
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Answer:

The coefficient of Z₂ is 1.

Explanation:

From the question given above:

X + ZY —> XY + Z₂

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X + ZY —> XY + Z₂

There is 1 atom of Z on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of ZY as shown below:

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There are 2 atoms of Y on the left side and 1 atom on the right side. It can be balance by putting 2 in front of XY as shown below:

X + 2ZY —> 2XY + Z₂

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2X + 2ZY —> 2XY + Z₂

Now the equation is balanced.

Thus, the coefficient of Z₂ is 1.

8 0
2 years ago
How many grams in 11.9 moles of sulfur? Avogadro’s number: 6.02x1023 atoms = 1 mole Molar mass of sulfur: 32.06 g sulfur = 1 mol
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Answer:

Mass = 0.37 g

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by putting values,

11.9 mol = mass/ 32.06 g/mol

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Mass = 0.37 g

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