8. If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A?
1 answer:
We have that you can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
From the question we are told
If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A
Generally the equation for the Concentration Volume relationship is mathematically given as
Therefore
You can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
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Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is .
Explanation:
When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.
For example, chemical equation for oxidation of methane is as follows.
Number of atoms present on reactant side are as follows.
- C = 1
- H = 4
- O = 2
Number of atoms present on product side are as follows.
- C = 1
- H = 2
- O = 3
To balance this equation, multiply by 2 on reactant side. Also, multiply
by 2 on product side. Hence, the equation can be rewritten as follows.
Now, the number of atoms present on reactant side are as follows.
- C = 1
- H = 4
- O = 4
Number of atoms present on product side are as follows.
- C = 1
- H = 4
- O = 4
Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.
Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is .