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sleet_krkn [62]

4 years ago

14

This is the name to a type of bank account used by a person who wants to safely store their money but have immediate access to i

t for purchases.

2 answers:

Molodets [167]4 years ago

7 0

A checking account allows you to keep your money in the a bank account but you have a card you can use at stores.

kaheart [24]4 years ago

3 0

Explanation: checking

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Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital

shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= $\frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}$

= $\frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}$

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

$\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}$

using K/N = k

$\frac{s}{\delta +n-s}.\frac{n}{kt}$

plugging the value of kt*

$\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}$

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) = n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0

3 years ago

PLEASE HELP ME WITH THIS PLS PLS PLS

AveGali [126]

The first once is c and and is a

3 0

2 years ago

Your total sales during a six-hour shift were $1,200. Your individual performance in terms of sales per hour would be:

Anit [1.1K]

Answer:

b. $200

Explanation:

The computation of the individual performance is shown below:

= Total sales ÷ number of shift hours

= $1,200 ÷ 6 hours

= $200

It means that per hour, the individual performance is $200

We simply divide the total sales by the number of shift hours, so that the sales per hour can determined

It shows a relationship between the total sales and the number of shift hours

4 0

3 years ago

A financial adviser has just given you the following advice: "Long-term bonds are a great investment because their interest rat

Nikolay [14]

Answer:

No

Explanation:

Long term bonds might not be great investments if the interest rate fall or even slide into negative value in the future. This means that the bond will become insignificant in value.

Cheers

3 0

3 years ago

Read 2 more answers

All of the following must be disclosed on municipal bond trade confirmation EXCEPT: A "In Whole" call dates B For revenue bonds,

Mashcka [7]

Answer:

The correct answer is D. For general obligation bonds, the source of income backing the issue.

Explanation:

There is no requirement to disclose the source of income that supports a general obligation issue because it must be a taxing power. The MSRB requires that the type of income that supports an income bond issue be disclosed, as well as the name of the corporate guarantor of the industrial income bonds. The dates of the calls "in their entirety" must also be disclosed in the customer confirmations, as they may affect the price of the issuance according to the rules of the MSRB (the MSRB requires that if a bond quoted based on performance is negotiated with a premium, and if it is enforceable "in its entirety" on pre-established dates and prices, then the dollar price must be calculated at the date of the call instead of the expiration date, since it is most likely to be called ).

5 0

3 years ago