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Svet_ta [14]
3 years ago
8

Steps for solving 4(3x-6)=24

Mathematics
2 answers:
zepelin [54]3 years ago
7 0
Multiply 3x*4=12x   -6*4=-24 so 12x-24=24 add 24 and it would be 12x=48 divide by 12 and x=4
SVETLANKA909090 [29]3 years ago
7 0
C. A is correct. B is correct. D is correct.
                                   
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What is the difference between the fractions? Use the number line to help find the answer.
NNADVOKAT [17]

Answer:

The difference is \frac{3}{10}

Step-by-step explanation:

We must find the common denominator of the fractions.

The common denominator of \frac{1}{2} and \frac{1}{5} is 2*5=10; therefore we have

\frac{1}{2}=\frac{5}{10}

\frac{1}{5} =\frac{2}{10}

now it is easy to subtract \frac{5}{10} -\frac{2}{10} using the number line: we have to move \frac{3}{10} units to the left in order to get to \frac{2}{10}.

Thus our answer is

\boxed{\frac{1}{2} -\frac{1}{5}=\frac{3}{10} }

3 0
3 years ago
Read 2 more answers
The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

3 0
3 years ago
Solve the following equation: 7x - 8 = 3x + 12
Paul [167]
X=5
7(5)-8=35-8=27
3(5)+12=15+12=27
3 0
3 years ago
Please help soon- The weight of oranges growing in an orchard is normally distributed with a mean
Leya [2.2K]
5 oz. Hope this helped!
5 0
3 years ago
I have to find the circumference of 15 cm​
Pie

Answer:

r = 2.39 and C=2πr=2·π·2.39≈14.99997

Step-by-step explanation:

Using the formula

C=2πr

Solving for r=C 2π=15

2·π≈2.38732

and then u round up the 7 told the 8 to go up.

2.39

7 0
3 years ago
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