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3 years ago

8

If the quantity of reactants used in a chemical reaction increase, then the quantity of the products produced will also be incre

ased. This is because

1 answer:

oksian1 [2.3K]3 years ago

4 0

Answer:

the amount of reactants is always directly proportional to the product

Explanation:

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How many grams of Fe can be produced when 5.50 g of Fe2O3 reacts?

vichka [17]

Answer:

3,85 g of Fe

Explanation:

1- The first thing to do is calculate the molar mass of the Fe2O3 compound. With the help of a periodic table, the weights of the atoms are searched, and the sum is made:

Molar mass of Fe2O3 = (2 x mass of Fe) + (3 x mass of O) = 2 x 55.88 g + 3 x 15.99 g = 159.65 g / mol

Then, one mole of Fe2O3 has a mass of 159.65 grams.

2- Then, the relationship between the Fe2O3 that will react and the iron to be produced. With the previous calculation, we can say that with one mole of Fe2O3, two moles of Fe can be produced. Passing this relationship to the molar masses, it would be as follows:

1 mole of Fe2O3_____ 2 moles of Fe

159.65 g of Fe2O3_____ 111.76 g of Fe

3- Finally, the calculation of the mass that can be produced of Fe is made, starting from 5.50 g of Fe2O3

159.65 g of Fe2O3 _____ 111.76 g of Fe

5.50 g of Fe2O3 ______ X = 3.85 g of Fe

<em>Calculation: 5.50 g x 111.76 g / 159.65 g = 3.85 g </em>

The answer is that 3.85 g of Fe can be produced when 5.50 g of Fe2O3 react

7 0

3 years ago

(2pts) During the Purification of Lactate Dehydrogenase (LDH) experiment, you will need 50ml of buffer A150. Buffer A150 is 30mM

torisob [31]

Answer:

The answer is " $20 \ mL$ "

Explanation:

Given:

Molarity= number of moles

because it is 1 Liter

$\to \frac{0.03\ moles}{1.5 moles}=0.02\ L= 20 \ mL \ of\ Tris\\\\$

therefore,

it takes 20 mL of Tris.

$\to \frac{0.150 \ moles}{5\ moles} =0.03\ L\\\\$

$= 30 \ mL \ of\ Nacl$

So, take $20 \ mL\ of\ NaCl.$

6 0

3 years ago

What's the difference between a mole of propane and a gram of propane? <br>

kobusy [5.1K]

B. A gram would have a lot more molecules of propane than a mole

5 0

2 years ago

Convert 22 grams of copper Il chloride (Cucl2) to moles. <br>with work please

Fittoniya [83]

Hope this helps!

https://youtu.be/MT5tKijKZwQ

5 0

3 years ago

Read 2 more answers

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

posledela

The question is incomplete, here is the complete question:

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

Suppose 6 moles of silver nitrate react. The reaction consumes___ moles of copper. The reaction produces __ moles of copper(II) nitrate and __ moles of silver.

<u>Answer:</u> The amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

<u>Explanation:</u>

We are given:

Moles of silver nitrate = 6 moles

For the given chemical reaction:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

<u>For copper metal:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of copper metal

So, 6 moles of silver nitrate will react with = $\frac{1}{2}\times 6=3mol$ of copper metal

Moles of copper reacted = 3 moles

<u>For copper(II) nitrate:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 1 mole of copper(II) nitrate

So, 6 moles of silver nitrate will produce = $\frac{1}{2}\times 6=3mol$ of copper(II) nitrate

Moles of copper(II) nitrate produced = 3 moles

<u>For silver metal:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6 moles of silver nitrate will produce = $\frac{2}{2}\times 6=6mol$ of silver metal

Moles of silver metal produced = 3 moles

Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

6 0

3 years ago