Answer:
----
--Br--
Explanation:
The steps involved in predicting the structure of the alkyl bromide compound are outlined below.
1) An examination of the product shows that the product could only be formed by a substitution reaction.
2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.
Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is ------Br--. A pictorial diagram of the alkyl bromide compound is also attached.
It is formed when a metal element is chemically combined to a nonmetal. The metal element will form a positive ion and the nonmetal will form a negative ion. They will then combined to form a very strong bond with very strong electrostatic forces between the particles.
<h2><u>Answer:</u></h2>
The correct answer is A) 1.04 mol Cu
{65.8 g / 63.55 g/mol}
= 1.04 mol Cu
Explanation:
In 63.55 g of copper metal there are 1 m
o
l of C
u atoms. By dividing the mass of Cu and molar mass, we can easily get the number of moles.
Answer:
Flammability is a material’s ability to burn in the presence of <u><em>oxygen.</em></u>
Explanation:
Flammability can be described as the ability of a substance to get ignited. Flammability will lead to fire or combustion. Some substances are highly flammable like Benzene. Other tend to be just flammable. And there are also compounds which will nor be flammable at all as they won't react with oxygen. Examples of these substances include helium, steel or glass.
The flammability of a substance shall be considered a very important aspect when storing or transporting a substance.
