We have that F is proportional to m1. Hence, we have that F=m1*c when we change the first mass. We also have that F=m2*c when we only change the 2nd mass. Since F scales inversely with the square of the distance, we have that

. Combining all of the facts above, we get that F=c*

where c is a constant.
First you want to figure out what exactly it is you are looking for. We are looking for "capital letters that have rotational symmetry but do not have line symmetry"
So:
1. Must have rotational symmetry.
This means that if we rotate the capital letter 180 deg, either clockwise or counterclockwise, it will still look the same
2. Must not have line symmetry.
If an object has line symmetry, it means that if you draw a line down the middle (in any way), it will be symmetrical on both sides. We need capital letters that do not fit that condition.
Now we look at all capital letters.
We find that H, I, N,O, S, X, and Z are all rotationally symmetrical. Think about it. If you rotate them, they still look the same.
But, we have to make sure they do not have line symmetry. If we draw a line right down the middle of H, I, O and X (**note, the have multiple lines of symmetry), they are symmetrical on both sides of the line.
Now we are left with N, S, and Z
Answer:
Step-by-step explanation:
For Mr Rowley,
Ratio of Number of home works to the number of exit tickets =
= 
= 6:7
For Ms Rivera,
Ratio of Number of home works to the number of exit tickets = 
= 
= 6:7
Since, both the ratios are same, fractions will be proportional.

Divide the numerical coefficients and write the quotation in simplest form
Answer:
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Diameter of a circle is 8 cm. Then find out the area and perimeter of the circle.
❥
Area of circle is 50.29(≈)cm² and perimeter of circle is 25.14(≈)cm.
❥
•Given :-
Diameter of the circle = 8 cm.
•To find :-
Area and perimeter of the circle.
• Solution :-
Let the radius of the circle be r cm.
Diameter = 8 cm.
We know,
★
So, Radius (r) = 8/2= 4 cm.
We know,
★
Area of circle= πr²
→Area of circle=
→Area of circle=
→Area of circle= 50.29(≈)cm²
____________________________
We know,
★
Perimeter of circle= 2πr
→ Perimeter of circle=
→Perimeter of circle=25.14(≈)cm