To solve this problem you must follow the steps below:
1. The problem says that:
- The<span> hot air balloon is at an altitude of 240 feet.
- It descends at 30 feet per minute.
2. Therefore, you have:
x: the time in minutes.
y: the altitute in feet.
3. Keeping all this information on mind, you can write the following equation:
y=240-30x
4. Therefore, as you can see, the answer is:
</span>
y=240-30x
28, by the way you could’ve just used a calculator
∠BDC=30, so ∠CBD + ∠BCD=180-30=150
ΔDBC is isosceles, so ∠CBD=∠BCD=half of 150=75
∠ABC=∠ABD-∠CBD=155-75=80
ΔABC is isosceles, so ∠ABC=∠ACB=80
∠BAC=180-80-80=20
Distribute first
a(b+c)=ab+ac
7y(8y-7)=56y^2-49y
now we have
56y^2-49y+46y
56y^2-3y
tada
A=lw. Is the answer. Hope it helps
