Find the critical value tc for the confidence level c=0.98 and sample size n=18

Mathematics

1 answer:

Mariulka [41]2 years ago

6 0

Answer step-by-step explanation:

We know that the critical t value for a 98% confidence level for a sample of size n = 18:

Finding degrees of freedom (n-1) = 17

-search the information in table t for 0.98 and find that t = 2.567

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The graph below shows the value of Edna's profits f(t), in dollars, after t months:

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Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
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$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the 9th month
 $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: B. −11.63 dollars per month.