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lorasvet [3.4K]
3 years ago
14

Jonah is purchasing a car that is on sale for 15% off. He knows the function that represents the sale price of his car is c(p) =

0.85p, where p is the original price of the car. He also knows he has to pay 9% sale's tax on the car. The price of the car with tax is f(c) = 1.09c, where c is the sale price of the car. Determine the composite function that can be used to calculate the final price of Jonah's car by solving for f[c(p)].
answers
A.f [c(p)] = 0.9265cp
B. f[c(p)] = 0.9265p
C. f [c(p)} = 1.94cp
D. f [c(p)] = 1.94p
Mathematics
1 answer:
nika2105 [10]3 years ago
7 0
The answer is b, f[c(p)]=0.9265p.

f[c(p)]=f(0.85p)=1.09(0.85p)=0.9265p

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In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen
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Answer:

a) P' = P

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b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

\frac{dP}{dt} = P

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

P(t) = P_0e^{kt}

where P_0 = 24 is the initial population

After 6 month (t = 1), the population is doubled to 48

P(1) = 24e^k = 48

e^k = 2

k = ln(2) = 0.693

Therefore P(t) = 24e^{0.693t}

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

24e^{0.693t} = 1000000

e^{0.693t} = 1000000 / 24 = 41667

0.693t = ln(41667) = 10.64

t = 10.64 / 0.693 = 15.35

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c. P' = P_0ke^{kt}

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

24e^{0.5k) = 48

0.5k = ln2 = 0.693

k = 1.386

Therefore, P' = 1.386*24e^{1.386t}

At the mid of the 3rd year, where t = 2.5, we can calculate P'

P' = 1.386*24e^{1.386*2.5} = 1064.67 rabbits/year

4 0
2 years ago
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Answer: Fact families are 3 numbers that make up a set of related math facts

Step-by-step explanation:

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7 0
2 years ago
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Gavin plans to mix a batch of tangerine paint. He expects to have a total of 5 3/10 ounces of paint after he mixes the amounts o
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3 0
3 years ago
PLS HELP!!!!!
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Answer:If you would like to know what will the approximate population be after 3 years, you can calculate this using the following steps:

an initial population ... 298 quail

an annual rate ... 8%

an exponential function to model the quail population:

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Therefore, the slope of the line is 7/4 OR 1.75.

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