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3 years ago

If 3600 j of work is done in 3.0 s what is the power0.00083W1200W3600W11000W

Physics

2 answers:

ivanzaharov [21]3 years ago

8 0

Answer : Power, P = 1200 Watts.

Explanation :

It is given that,

Work done, W = 3600 J

Time taken to complete the work, t = 3 s

The power is defined as the work done per unit time. The SI unit of power is watts.

Mathematically, it can be written as :

$P=\dfrac{W}{t}$

$P=\dfrac{3600\ J}{3\ s}$

P = 1200 Watts.

So, the correct option is (B) " 1200 W ".

Hence, this is the required solution.

Viktor [21]3 years ago

5 0

Answer:

1200 W

Explanation:

Power is given by the ratio between work done and time taken:

$P=\frac{W}{t}$

where W is the work done and t the time taken.

In this problem, W = 3600 J and t = 3.0 s. Therefore, the power in this exercise is

$P=\frac{3600 J}{3.0 s}=1200 W$

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The sun rotates once in 25.05 days. That is 601.2 hours. so the sun's rotational speed is 0.0017 rotations per hour. what is the

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2 years ago

Use the equation PiVi PfVf. Assume that Pi 101 kPa and Vi 10.0 L. If Pf 43.0 kPa, what is Vf

iren2701 [21]

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3 years ago

What is the average velocity of an arrow that travels 12 m [E] in 0.15 s?

sergij07 [2.7K]

Velocity is defined as Distance divided by Time.
In other words, V = D/T.

Now that we have our formula, we can solve.
Let's plug in the numbers we have.

We have 12m [East (direction not necessary when solving yet)] for our distance, and 0.15s as our time.

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3 years ago

A banked highway is designed for traffic moving at v 8 km/h. The radius of the curve = 330 m. 50% Part (a) Write an equation for

Monica [59]

Question

A banked highway is designed for traffic moving at v 8 km/h. The radius of the curve = 330 m. 50% Part (a) Write an equation for the tangent of the highway's angle of banking. Give your equation in terms of the radius of curvature r, the intended speed of the turn v, and the acceleration due to gravity g

Part (b) what is the angle of banking of the highway? Give your answer in degrees

Answer:

a. Equation of Tangent

tan(θ) = v²/rg

b. Angle of the banking highway

θ = 0.087°

Explanation:

Given

Radius of the curve = r = 330m

Acceleration of gravity = g = 9.8m/s²

Velocity = v = 8km/h = 8 * 1000/3600

v = 2.22 m/s

a . Write an equation for the tangent of the highway's angle of banking

The Angle is calculated by

tan(θ) = v²/rg

θ = tan-1(v²/rg)

Part (b) what is the angle of banking of the highway? Give your answer in degrees

θ = tan-1(v²/rg)

Substituting the values of v,g and r

θ = tan-1(2.22²/(330 * 9.8)

θ = tan-1(0.001523933209647)

θ = 0.087314873580116°

θ = 0.087°

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2 years ago