Answer:
The following options are true;
a) Electron transfer in the ETC is coupled to proton transfer form the matrix to the intermembrane space
c)The outer membrane of mitochondria is readily permeable to small molecules and hydrogen ions.
d) Electron carriers in the mitochondrial matrix include ubiquinone (coenzyme Q), FMN, and cytochrome c.
f)Electron carriers are organized into four complexes of proteins and prosthetic groups
Explanation:
ETC involves series of steps in which electrons are passed rapidly from one component to the next to the endpoint of the chain, where the electrons reduce molecular oxygen, producing water. This requirement for oxygen in the final stages of the chain can be seen in the overall equation for cellular respiration, which requires both glucose and oxygen.
A complex is a structure consisting of a central atom, molecule, or protein weakly connected to surrounding atoms, molecules, or proteins. The electron transport chain is an aggregation of four of these complexes (labeled I through IV), together with associated mobile electron carriers. The electron transport chain is present in multiple copies in the inner mitochondrial membrane of eukaryotes and the plasma membrane of prokaryotes.
I think its likely to explode
Answer:
Yes, it will float.
Explanation:
It is given that,
A liquid has a density of 0.85 g/cm³.
We know that, the density of water is 1 g/cm³.
The density of the liquid is less than that of water. If the density of the liquid is less than that of water, it will float in it. Hence, if you pour some of the liquid into a glass of water, it will float.
Answer:
F_net = 1.125 10⁻⁶ N
positive direction of the x axis
Explanation:
The electric force is given by Coulomb's law
F =
also used charge of equal sign repel each other.
We appease this information to our problems
the charge q₁ is positive and the charge q₃ is positive for which the force is repulsive; ; a charge q₂ is negative so the force is attractive.
If we apply that the forces are vectors
F_net = - F₁₃ + F₂₃
F_net =
F_net = k q₃ ( )
let's look for the distances
r₁₃ = 2-0 = 2 cm = 2 10⁻² m
r₂₃ = 4-0 = 4 cm = 4 10⁻² m
let's substitute
F_net = 9 10⁹ 5 10⁻⁹ ( )
F_net = 45 (- 0.5 10⁻⁷ + 0.75 10⁻⁷)
F_net = 1.125 10⁻⁶ N
the positive sign indicates that the outside has a positive direction of the x axis, that is, it is to the right