A mover pushes a 46.0kg crate 10.3m across a rough floor without acceleration. How much work did the mover do (horizontally) pus
hing the crate if the effective coefficient of friction was 0.50
1 answer:
Answer:
<h3>2,321.62Joules</h3>
Explanation:
The formula for calculating workdone is expressed as;
Workdone = Force * Distance
Get the force
F = nR
n is the coefficient of friction = 0.5
R is the reaction = mg
R = 46 ( 9.8)
R = 450.8N
F = 0.5 * 450.8
F = 225.4N
Distance = 10.3m
Get the workdone
Workdone = 225.4 * 10.3
Workdone = 2,321.62Joules
<em>Hence the amount of work done is 2,321.62Joules</em>
You might be interested in
Answer:
cross out the false piece in blue and write the true piece in red
Explanation:
F/18=2/3
F=2×18/3
F=12N
Answer:
Wavelength is 0.5
Explanation:
To work it out, you divide Wave speed by the Frequency (24÷48=0.5)
The combined amount of kinetic and potential energy of its molecules
The correct answer is “C” ultrasound. Hope this helps!
