The formula we can use here is:
g = G m / r^2
where g is gravity, G is gravitational constant, m is
mass, and r is radius
Since G is constant, therefore we can equate two
situations:
g1 m1 / r1^2 = g2 m2 / r2^2
(10 m/s^2) r1^2 / m1 = g2 * (1/2 r1)^2 / (1/8 m1)
<span>g2 = 5 m/s^2</span>
Deceleration = 29250 / 6500 = 4.5 m/s^2
Answer:
See attachment
Explanation:
The diagram attached is a sketch of rays when the object is placed between the lens and focal point. As can be seen, the image in such cases is always on the same side of lens as the object. It is formed beyond the focal point from the lens and is magnified
Answer:
203.1J
Explanation:
Given parameters:
Mass = 65kg
Speed = 2.5m/s
Unknown:
Kinetic energy of jogger = ?
Solution:
To solve this problem, we use the kinetic energy equation:
K.E =
m v²
m is the mass
v is the velocity
Now insert the parameters and solve;
K.E =
x 65 x 2.5² = 203.1J