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3 years ago

Question 11 of 11 | Page 11 of 11

Physics

1 answer:

KiRa [710]3 years ago

3 0

Answer:

Decreases the time period of revolution

Explanation:

The time period of Cygnus X-1 orbiting a massive star is 5.6 days.

The orbital velocity of a planet is given by the formula,

v = √[GM/(R + h)]

In the case of rotational motion, v = (R +h)ω

ω = √[GM/(R + h)] /(R +h)

Where 'ω' is the angular velocity of the planet

The time period of rotational motion is,

T = 2π/ω

By substitution,

Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.

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P.E QUESTION

vredina [299]

The answer is 5 maybe

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3 years ago

Which statement supports the idea that the Earth rotates on its axis?

Ivenika [448]

Answer:

Explanation:

because the other would not make sense

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3 years ago

Consider a basketball player spinning a ball on the tip of a finger. If a player performs 1.99 J of work to set the ball spinnin

scoundrel [369]

To solve this problem it is necessary to apply the concepts related to rotational kinetic energy, the definition of the moment of inertia for a sphere and the obtaining of the radius through the circumference. Mathematically kinetic energy can be given as:

$KE= I\omega^2$

Where,

I = Moment of inertia

$\omega =$ Angular velocity

According to the information given we have that the radius is

$\Phi= 2\pi r$

$0.749m = 2\pi r$

$r = 0.1192m$

With the radius obtained we can calculate the moment of inertia which is

$I = \frac{2}{3}mr^2$

$I = \frac{2}{3}(0.624)(0.1192)^2$

$I = 5.91*10^{-3} kg \cdot m^2$

Finally, from the energy equation and rearranging the expression to obtain the angular velocity we have to

$\omega = \sqrt{\frac{2KE}{I}}$

$\omega = \sqrt{\frac{2(1.99)}{5.91*10^{-3}}}$

$\omega = 25.95rad/s$

Therefore the angular speed will the ball rotate is 25.95rad/s

8 0

3 years ago

The volume of a gas is reduced from 4 l to 0.5 l while the temperature is held constant. How does the gas pressure change?

shusha [124]

Answer:

The pressure increases by a factor 8

Explanation:

For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:

$p_1 V_1 = p_2 V_2$

where

$p_1$ is the initial pressure

$p_2$ is the final pressure

$V_1$ is the initial volume

$V_2$ is the final volume

For the gas in this problem, the volume is reduced from

$V_1 = 4 L$

$V_2 = 0.5 L$

so we can rewrite the equation as

$\frac{p_2}{p_1}=\frac{V_1}{V_2}=\frac{4 L}{0.5 L}=8$

this means that the pressure of the gas will increase by a factor 8.

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Factors that affect the light intensity received from a source

Roman55 [17]

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3 years ago