Question

Question 11 of 11 | Page 11 of 11

Answer 1

Answer:

Decreases the time period of revolution

Explanation:

The time period of Cygnus X-1 orbiting a massive star is 5.6 days.

The orbital velocity of a planet is given by the formula,

                                        v = √[GM/(R + h)]

In the case of rotational motion, v = (R +h)ω

                                         ω = √[GM/(R + h)] /(R +h)

Where 'ω' is the angular velocity of the planet

The time period of rotational motion is,

                                     T = 2π/ω

By substitution,

                                      T = 2π(R +h)√[(R + h)/GM]

Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.