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Scorpion4ik [409]
3 years ago
8

When you ride a bike and make a turn, you can feel your body trying to

Physics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:first law

Explanation:

it states the a body in motion or rest maintain its state until an external force is acted on it

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Groundwater is the water found underground in the cracks and spaces in soil, sand and rock. It is stored in and moves slowly through geologic formations of soil, sand and rocks called aquifers.


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2 years ago
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Which item is not considered electromagnetic energy?
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Sound waves are known to be the one that's not considered as a type of electromagnetic energy. As for microwaves and x-rays, they tend to share the same frequencies that can be considered as electromagnetic, and sound waves have a different frequency than them.
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3 years ago
The pitch of a note corresponds to which property of sound wave
Ksivusya [100]
A high pitch sound corresponds to a high-frequency sound wave and a low pitch sound corresponds to a low-frequency sound wave. So, the pitch of a note corresponds to the amount of frequency of a sound wave. Hope this helped!
8 0
3 years ago
A spherical capacitor is formed from two concentric sphericalconducting shells separated by vacuum. The inner sphere has radius1
zubka84 [21]

Explanation:

(1).  Formula to calculate the potential difference is as follows.

       \Delta V = -\int E dr

                  = -\int \frac{kq}{r^{2}} dr

                 = \frac{kq}{r_{f}} - \frac{kq}{r_{i}}

                 = \frac{kq(r_{f} - r_{i})}{r_{f}r_{i}}

                 = \frac{9 \times 10^{9} \times 3.30 \times 10^{-9}(0.1 - 0.015)}{0.1 \times 0.015}

                = 38.7 volts

Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.

(2).  Now, formula to calculate the energy stored in the capacitor is as follows.

           E = \frac{1}{2}QV

              = \frac{1}{2} \times 3.30 \times 10^{-9} \times 3.87 V

              = 6.39 \times 10^{-8} J

Thus, the electric-field energy stored in the capacitor is 6.39 \times 10^{-8} J.

7 0
3 years ago
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A satellite is launched to orbit the Earth at an altitude of 3.25 107 m for use in the Global Positioning System (GPS). Take the
Korolek [52]

Answer:Orbital period =21.22hrs

Explanation:

given that

mass of earth M = 5.97 x 10^24 kg

radius of a satellite's orbit, R=  earth's radius + height of the satellite

6.38X 10^6 +  3.25 X10^7 m =3.89 X 10^7m

Speed of satellite, v= \sqrt GM/R

where G = 6.673 x 10-11 N m2/kg2

V= \sqrt (6.673x10^-11 x 5.97x10^ 24)/(3.89 X 10^ 7m)

V =10,241082.2

v= 3,200.2m/s

a) Orbital period

\sqrt GM/R = \frac{2\pi r}{T}

V= \frac{2\pi r}{T}

T= 2 \pi r/ V

= 2 X 3.142 X 3.89 X 10^7m/ 3,200.2m/s

=76,385.1 s

60 sec= 1min

60mins = 1hr

76,385.1s =hr

76,385.1/3600=21.22hrs

3 0
3 years ago
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