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Ymorist [56]
3 years ago
8

your soccer team isn’t holding a silent auction dinner as a fundraiser to pay for school uniforms. The list shows all the expens

es for the silent auction, 1) a tablet costs $280 2) football tickets that cost $100 3) a gift card that cost $20 4) the cost of the food is $400. The members of the soccer team will be selling tickets to the silent auction. A ticket to the silent auction includes chances to win prizes and dinner. The ticket cost is set so that 50 tickets will pay for the cost of food and prizes and food. Part a determine the cost per ticket. Part B build a function that can be used to find the total profit, f(x), the soccer team earns by selling x tickets. Show your work to build a function. Part C your soccer team needs to raise at least $300 more than the total cost of the expenses. What is the minimum number of tickets that must to be sold in order for your team to reach their goal? Use the mathematics to justify your response.
Mathematics
2 answers:
Eva8 [605]3 years ago
7 0

ghjjjiiiiijijuiuijjjjjijjjjjj

klasskru [66]3 years ago
5 0
What would the function equation be
You might be interested in
Please help !! i’m not quite getting what the equation can possibly be ? thank u !
Reika [66]
I think the answer is y=1/4x+2 :)
4 0
3 years ago
How do I write this fraction as a decimal 14 3/5
Softa [21]

we have

14 \frac{3}{5}

This is a mixed number

we know that

A mixed number is a combination of a whole number and a fraction.

So

14 \frac{3}{5} is equal to

14 +\frac{3}{5}

where

14 is the whole number

\frac{3}{5} is the fraction

\frac{3}{5}=0.60

14 +\frac{3}{5} =14+0.60\\ \\ =14.60

therefore

the answer is

14.60

3 0
3 years ago
Read 2 more answers
Classwork: Multiply, Add, and Subtract Polyno
V125BC [204]
I hope this was helpful

3 0
1 year ago
A textbook company keeps track of its daily cost for printing whole textbooks to different schools, but can only print up to 500
seraphim [82]
Part A: Chose some value for x, that means any amount of books to print for example 100 books, so x=100
Replace x=100 in C(x) and solve:
C(100)=3.5*100+1200=1550
Part B: Replace C(x) by 1900 and solve for x from the given equation:
1900=3.5x+1200
3.5x=1900-1200
x=700/3.5= 200
Part C: the statement C(20)=1270 means that 1270 is the cost for printing 20 books.
Part E: C(40.5)=1341.75 I think this statement is incorrect given the context because x means number of books to print so this value must be an integer number.
8 0
3 years ago
A car rental agency has 150 cars. The owner finds that at a price of $48 per day, he can rent all the cars. For each $2 increase
hram777 [196]
Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.

Let x be the number of $2 increases in price, then the revenue from renting cars is given by
(48 + 2x) \times (150 - 4x)=7,200+108x-8x^2.

Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
5(150-4x)=750-20x

Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>(7,200+108x-8x^2)-(750-20x)=6,450+128x-8x^2

For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>\frac{d}{dx} (6,450+128x-8x^2)=0 \\  \\ 128-16x=0 \\  \\ x= \frac{128}{16} =8

The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.

Therefore, the </span><span>rental charge will maximize profit is $64.</span>
3 0
3 years ago
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