Step 1) Multiply 2 by 3
<em>5x+6 = 2x+3x+6</em>
Step 2) Combine like terms
<em>5x+6 = 5x+6</em>
Step 3) Add 5x and 6 to both sides
Answer:
<em>0 = 0</em>
Given :
The Mad Hat Company must ship two different-sized boxes: The small ones cost them 45 cents each and weigh 6 ounces, and the large ones weigh 25 ounces and cost $1.20 each.
The total shipment this morning weighed 20 pounds 7 ounces and cost $18.45.
To Find :
How many packages of each size were shipped.
Solution :
We know, 1 pound = 16 ounces.
So, 20 pound = 20×16 = 320 ounces.
Let, number of large and small box are l and s.
So,
25l + 6s = 327 ...1)
0.45s + 1.20l = 18.45 ...2)
Solving both the equations, we get :
x = 9 and y = 17
Therefore, package smaller and big size are 17 and 9 respectively .
Hence, this is the required solution.
Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Even integer: 2 x a, where a is a natural number without 0;
Odd integer : 2 x b + 1 , where b is a natural number;
So, 2 x a + 2 x b+ 1 = 2 x ( a + b ) + 1, which is an odd integer.
