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Sindrei [870]
3 years ago
6

A 3ed degree binomial with a constant term of 8

Mathematics
1 answer:
Svet_ta [14]3 years ago
7 0

Answer:

4m³+8 is a 3rd degree binomial with constant term of 8.

Step-by-step explanation:

  • A binomial expression consists of two terms.

For example,

m+n is a binomial, where m and n are two terms.

  • As we know that the degree of the polynomial is said to be the highest exponent of any of the terms.

For example, in expression 7m + 3, the exponent of m is 1. So it is 1st degree polynomial.

Similarly, in the expression 10m²+9m, variable m has the highest exponent which is 2. So it is 2nd degree polynomial.

Now, let us write a 3rd degree binomial with a constant term of 8

4m³+8

As it has two terms which are 4m³ and 8, Therefore, it would be called binomial.

Also the highest exponent with variable m is 3. Therefore it would be a 3rd degree binomial with constant term of 8.

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How many terms are in the arithmetic sequence 1313, 1616, 1919, ……, 7070, 7373?
Ede4ka [16]
The formula in getting the arithmetic sequence:
an = a1<span> + (n – 1)d.
</span>
We can substitute the values in order for us to know how many terms the sequence has.

an = 7373
a1 = 1313
d = 303

an = a1<span> + (n – 1)d
</span>7373 = 1313 + (n-1) 303
7373 = 1313 + 303n - 303
-303n = 1313 - 303 - 7373
303n = -1313 + 303 + 7373
303n = 6363
n = 21

So, there are 21 terms in the sequence given.

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LUCKY_DIMON [66]

Answer:

C

Step-by-step explanation:

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