Help me again and explain how you got the answer thans
1 answer:
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For #1. Step 1: Set the equations equal to one another: (3x + 20) = (2x + 40)
Step 2: Subtract 2x on both sides of the equal sign: (3x-2x + 20) = (2x-2x + 40)
x + 20=40
Step 3: Subtract 20 on both sides of the equal sign: x + 20-20= 40-20
x=20
Step 4: plug in 20 for x: 3(20) + 20= 80 & 2(20) + 40= 80
Step 2: Subtract 2x on both sides of the equal sign: (3x-2x + 20) = (2x-2x + 40)
x + 20=40
Step 3: Subtract 20 on both sides of the equal sign: x + 20-20= 40-20
x=20
Step 4: plug in 20 for x: 3(20) + 20= 80 & 2(20) + 40= 80