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andre [41]
3 years ago
15

A solution conducts electric current. Can you use the property to determine if the solution is an acid or base? Explain please.

Chemistry
2 answers:
raketka [301]3 years ago
4 0
No, you cannot, because both acidic and basic solutions can conduct electric <span>currents.</span>
andriy [413]3 years ago
4 0
Ummm tricky 
 that is hard sometimes lol wait

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Match the scientists to their contributions to the development of the periodic table.
stiv31 [10]
Where’s the chart and scientists?
3 0
4 years ago
Part a the disproportionation of mn2+(aq) to mn(s) and mno2(s) in acid solution at 25 ∘c. calculate δg∘rxn.
ollegr [7]

Answer:

ΔG^{o} = -461198.3 J

Explanation:

Gibbs free energy is defined as the energy associated with a given chemical reaction which can be used to do work. Firstly, we need to figure out the chemical equation for the given problem. For the given problem, the chemical equation is:

Mn^{2+} _{(aq)} + 2e^{-}⇒Mn_{(s)}      E^{o} = -1.18 V

Mn^{2+} _{(aq)} + H_{2}O ⇒MnO_{2(s)} +4H^{+} + 2e^{-}E^{o} = -1.21 V

The addition of the two E^{o} gives the E_{cell} of the equation, i.e. -1.18-1.21 = -2.39 V.

Then, using the equation for ΔG^{o}, we have:

ΔG^{o} = n*F*E^{o} = 2*96485*-2.39 = -461198.3 J

4 0
4 years ago
Identify the standard metal cations in the active components of soaps
rjkz [21]
Answer is: standard metal cations are sodium cation (Na⁺), potassium cation (K⁺), magnesium cation (Mg²⁺) and calcium cation (Ca²⁺).
Soap<span> is a </span>salt<span> of a </span>fatty acid. When soap have sodium and potassim cations, that is toilet soap and when soap have magnesium and calcium cations, that soap is called <span>metallic soap.</span>
8 0
4 years ago
To determine the concentration of 20.00 mL of an unknown solution of a monoprotic acid, it is titrated with 0.1093 M sodium hydr
Elanso [62]

Answer:

d) 0.1202 M

Explanation:

Let's consider the neutralization reaction between NaOH and a generic monoprotic acid.

NaOH + HA → NaA + H₂O

The used volume of NaOH is 41.63 mL - 19.63 mL = 22.00 mL. The moles of NaOH are:

22.00 × 10⁻³ L × 0.1093 mol/L = 2.405 × 10⁻³ mol

The molar ratio of NaOH to HA is 1:1. The moles of HA that reacted are 2.405 × 10⁻³ moles.

The molar concentration of HA is:

2.405 × 10⁻³ mol / 20.00 × 10⁻³ L = 0.1202 M

7 0
3 years ago
In a classroom, which comparison would a teacher most likely use for describing a mole?
mihalych1998 [28]

Answer:

If you were speaking of the term mole as a skin condition then a teacher might compare it to a beauty spot. In the position your were speaking of it as an animal they might compare it to mouse a rat or a hamster. In the case you were speaking of a mole as a secret agent then a teacher might compare them to a double agent.

8 0
3 years ago
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