Answer:
7900N
Explanation:
35cm = 0.35m
When the object is at the rope center, its position at 3.44 / 2 =1.72m. We can find out the angle that the sagged rope makes with the horizontal
this means the rope makes with the vertical an angel of
90 - 11.5= = 78.5 degree
The tension of the 2 ropes, T, should balance with the object weight
= \frac{3160}{2*0.2} = 7900N[/tex]
Answer:
Check the explanation
Explanation:
Their is no data provided for the mass and length of pendulum in the picture.but it is very easy to check kinetic energy.KE is mv^2/2, m is the pendulum Bob and v is time dependent ,equation of displacement of SHM is given as x(t)=Asin(wt+∆) where ∆ is the phase angle now v=dX/dt _v=Awcos(wt+∆) and KE=
Thus w angular frequency of oscillation is√(g/l)
g acceleration due to gravity and l length of pendulum.so KE is same for pendulum having same mass and length otherwise KE expression with time will vary for all other cases.now check if all experiment pendulum have same mass and length otherwise KE will not be same.You can now easily verify.
Answer:
5.5 rad/s
Explanation:
The friction between the coin and the turntable provides the centripetal force that keeps the coin in circular motion. Therefore, we can write:
where
is the coefficient of friction
m is the mass of the coin
is the acceleration of gravity
is the angular speed
r is the distance of the coin from the centre of rotation
In this problem,
r = 11.0 cm = 0.11 m
The coin starts to slip when the centripetal force becomes larger than the maximum frictional force:
Solving for , we find the angular speed at which this happens:
You can figure this out using the equation for specific heat: q=mcΔT; where q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature (in °C or K).
In this case we're solving for q, given m = 20000 g, c = 4.18 j/g°C, and ΔT = 35°-0°=35°. This means q = 20000 x 4.18 x 35 = 2 926 000 J, or 2926 kJ.