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Ede4ka [16]
3 years ago
8

He's 76.2 W lightbulb uses 66.2 J of electrical energy every second. However, only 4.9 J of electrical energy is converted into

light energy of each check and what is the efficiency of the lightbulb? Give your answer as a percentage to at least three decimal places
Physics
1 answer:
iogann1982 [59]3 years ago
5 0

Answer:

7.402%

Explanation:

Given that the total electrical energy used by the bulb in every second is 66.2 J.

The useful energy converted to light energy is 4.9 J.

As efficiancy (in %) = (Useful energy)/(Total energy) x 100

So, the efficiency of the bulb = (4.9/66.2)x100=7.402%

Hence, the efficiency of the bulb is 7.402%.

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D. Gravitational force.

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3 years ago
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Charge is given in microcoulombs. What must you multiply the charge by to use Coulomb's
iVinArrow [24]

Answer:

Option A. 10¯⁶

Explanation:

To know which option is correct, we must bear in mind, the relationship between micro coulomb (μC) and coulomb (C). This is given below:

Recall:

1 μC = 10¯⁶ C

Therefore, to convert micro coulomb (μC) to coulomb (C), multiply the value given in micro coulomb (μC) by 10¯⁶.

Thus, option A gives the correct answer to the question.

7 0
3 years ago
Please help me!<br> Why is there more runoff in areas with high clay content?
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3 0
3 years ago
When you sneeze, the air in your lungs accelerates from rest to approximately 150km/h in about 0.50 seconds. What is the acceler
miss Akunina [59]
(150 km/hr) x (1000 m/km) x (hr/3600sec)  =  41-2/3 m/sec

Acceleration  =  (change in speed) / (time for the change)

Change in speed  =  (41-2/3 minus 0) = 41-2/3 m/s
Time for the change = 0.5sec.

Acceleration = (41-2/3 m/s) / (0.5 sec)  =  83-1/3 m/s² .

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3 years ago
. A milk truck carries milk with density 64.6 lbyft3 in a horizontal cylindrical tank with diameter 6 ft. (a) Find the force exe
Goryan [66]

Answer:

Explanation:

one end of tank will be circular in shape . Area of circle A

= π r² , r is radius of the circle

= 3.14 x 3²

A = 28.26 ft³

To calculate force  on the circular area , we first find pressure at the center of the circle which is at depth equal to r

pressure at the center = h d g ' here h = depth = r   , d = density of milk

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8 0
3 years ago
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