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MatroZZZ [7]
3 years ago
8

What are the two principle advantages of telescopes over eyes?

Physics
1 answer:
Stells [14]3 years ago
8 0

Answer:

i) Telescopes can be used to view far distant objects but the human eye can't view far distant objects.

ii) Telescopes uses two convex lenses producing a magnified image while the human eye only possesses one convex lens (image seen are smaller than that viewed under telescopes)

Explanation:

The telescopes can be used to view far distant objects due to their presence of two convex lenses. The two convex lenses are the objective lens (lens closer to object) and the eye piece lens (lens closer to eye). The object to be viewed forms an intermediate image first before the final image is seen using the eye piece lens.

The human eye only possess one convex lens and as such cannot view far ranged objects.

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A student needs to prepare 100.0 mL of vitamin C solution according to the directions in Part 1 of the experiment. S/he weighs o
Rudiy27

Answer:

4.99 mg of vitamin C are in the beaker.

Explanation:

Given that,

Weight of vitamin = 0.0499 g

Molar mass = 176.124 g/mol

Weight of water = 100.0 ml

We need to calculate the mg of vitamin C in the beaker

We dissolve 0.0499 g vitamin C in water to from 100.0 ml solution.

100 ml solution contain 49.9 mg vitamin C

Now, we take 10 ml of this vitamin C solution in breaker

Since, 100 ml solution =49.9 mg vitamin C

Therefore,

10\ ml\ solution =\dfrac{10\times49.9}{100}

10\ ml\ solution =4.99\ mg

Hence, 4.99 mg of vitamin C are in the beaker.

4 0
3 years ago
Light shines through a single slit whose width is 5.7 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a
lilavasa [31]

Answer:

\lambda = 570\ nm

Explanation:

Given,

Width of slit, W = 5.7 x 10⁻⁴ m

Distance between central bright fringe, L = 4 m

distance between central bright fringe and first dark fringe, y = 4 mm

Diffraction angle

tan \theta = \dfrac{y}{L}

tan \theta = \dfrac{4}{4\times 10^3}

\theta = 0.0572

Now.

W sin \theta = m \lambda

m = 1

5.7 \times 10^{-4} \times sin (0.0572) = 1 \times \lambda

\lambda = 569.99 \times 10^{-9}\ m

\lambda = 570\ nm

4 0
3 years ago
Two astronauts push on a satellite. One pushes in the positive x direction with a force of 42 N, and the other pushes in the pos
inessss [21]

The vectors adition we can find the magnitude of the force applied by the other astronaut is  11.25 N in the y direction

 

Parameters given

  • Force of an astronaut Fₓ = 42 N
  • Angle θ = 15º

To find

  • Force another astronaut

The force is a vector magnitude for which the addition of vectors must be used, a very efficient method to perform this sum is to add the components of each vector and devise constructing the resulting vector using trigonometry and the Pythagorean theorem.

Let's use trigonometry to find the other force

            tan θ = \frac{F_y}{F_x}

            F_ y = Fₓ tan θ

let's calculate

            F_y = 42 tan 15

            F_y = 11.25 N

Using the summation of vectors we can find the magnitude of the force applied by the other astronaut is 11.25 N in the y direction

Learn more about vector addition here:

brainly.com/question/15074838

4 0
2 years ago
A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loo
m_a_m_a [10]

Answer:

The induced emf  is  \epsilon  = 0.1041 \  V  

Explanation:

From the question we are told that

   The  radius of the circular loop is  r =  9.50 \ cm  =  0.095 \ m

     The  intensity of the wave is  I  =  0.0215 \ W/m^2

      The wavelength is  \lambda =  6.90\ m

Generally the intensity is mathematically represented as

         I  =  \frac{ c *  B^2  }{ 2 * \mu_o  }

Here  \mu_o is the permeability of free space with value  

         \mu_o  =  4 \pi *10^{-7} N/A^2

B is the magnetic field which can be mathematically represented from the equation as

          B  =  \sqrt{ \frac{ 2 *  \mu_o  *  I  }{ c} }

substituting values

          B  =  \sqrt{ \frac{ 2 *  4\pi *10^{-7} *   0.0215  }{ 3.0*10^{8}} }

          B  =  1.342 *10^{-8} \  T

The  area is mathematically represented as

       A =  \pi r^2

substituting values

       A =  3.142 *   (0.095)^2

       A = 0.0284

The angular velocity is mathematically represented as

        w =  2 *  \pi  *  \frac{c}{\lambda }

substituting values          

       w =  2 *  3.142   *  \frac{3.0*10^{8}}{ 6.90 }  

        w =  2.732 *10^{8} rad  \ s^{-1}  

Generally the induced emf is mathematically represented as

        \epsilon  =  N *  B  *  A  *  w * sin (wt )

At maximum induced emf  sin (wt)  =  1

    So

         \epsilon  =  N *  B  *  A  *  w

substituting values

         \epsilon  = 1  *    1.342 *10^{-8}   *  0.0284  *2.732 *10^{8}  

         \epsilon  = 0.1041 \  V  

         

7 0
3 years ago
Sics and Chemistry A (2nd Six Weeks) - SC3200SFA/01
Andreyy89
Force = Mass * Acceleration therefore the red ball with the higher mass will have more force and greater acceleration
3 0
3 years ago
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