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Genrish500 [490]
3 years ago
15

What technology produced the results illustrated here, and what is this technology used for?

Physics
2 answers:
IrinaVladis [17]3 years ago
6 0
Where is the phone ? Can’t answer without a picture of the problem
elixir [45]3 years ago
4 0

The results illustrated here were hidden by means of Obscurational Cloaking technology.

This technology is used to hide, conceal, obscure, and withhold results.

You might be interested in
LAST ONE! ASAP PLEASE
Doss [256]

Answer:

There are so many questions which one you don't know

4 0
3 years ago
Read 2 more answers
A 3.50 cm tall object is held 24.8 cm from a lens of focal length 16.0 cm. What is the image height?
Mandarinka [93]

Answer:

<h2>6.36 cm</h2>

Explanation:

Using the formula to first get the image distance

1/f = 1/u+1/v

f = focal length of the lens

u = object distance

v = image distance

Given f = 16.0 cm, u = 24.8 cm

1/v = 1/16 - 1/24.8

1/v = 0.0625-0.04032

1/v = 0.02218

v = 1/0.02218

v = 45.09 cm

To get the image height, we will us the magnification formula.

Mag = v/u = Hi/H

Hi = image height = ?

H = object height = 3.50 cm

45.09/24.8 = Hi/3.50

Hi = (45.09*3.50)/24.8

Hi = 6.36 cm

The image height is 6.36 cm

6 0
3 years ago
At what speed does a 1,248 kg compact car have the same kinetic energy as a 18,777 kg truck going 26 km/h?
notka56 [123]

The speed of car is 100.8km/h

KE =  \frac{1}{2} m(v \: truck ) {}^{2}

= 0.5 \times 18777 \times  \frac{26}{3.6} \times  \frac{26}{3.6}

= 489708.79j

=  \frac{1}{2}  \times 1248 \times( v \: car) {}^{2}

= 624v {}^{2}

so \: v {}^{2}  =  \frac{489708.7}{624}

= 784

v =  \sqrt{784}

v = 28m/s

v car= 28×3.6

=100.8km/h

Hence, the speed of the car is 100.8km/h

learn more about speed from here:

brainly.com/question/28326855

#SPJ4

3 0
1 year ago
4. A metal fork has a density of 7.8 g/cm ³. Is this fork made up of aluminum?
Morgarella [4.7K]
No, aluminum has a density near 2.7 g/cm^3 
<span>7.8 g/cm^3 is near the density of iron (or in the case of a fork, steel).
this is it

</span>
5 0
3 years ago
A certain superconducting magnet in the form of a solenoid of length 0.72 m can generate a magnetic field of 3.5 T in its core w
ira [324]

Answer:

55407

Explanation:

we have given that magnetic field B=3.5 T

current through the coil=90 A

Length of solenoid =0.72 m

we know the formula of magnetic field

B=\frac{\mu _0NI}{l}

so N=\frac{Bl}{\mu _0I}=\frac{3.5\times 0.72}{4\pi \times 10^{-6}\times 90}=55407.277=55407\ turns

so the number of turn in solenoid will be 55407

3 0
3 years ago
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