Suppose that Salim hits a 100 g fastball moving towards him at a speed of 42 m/s with his bat as shown in the image.the impulse
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Answer:
40 N
Explanation:
We are given that
Speed of system is constant
Therefore, acceleration=a=0
Tension applied on block B=T=50 N
Friction force=f=10 N
We have to find the friction force acting on block A.
Let T' be the tension in string connecting block A and block B and friction force on block A be f'.
For Block B
Where =Mass of block B
Substitute the values
For block A
Where Mass of block A
Substitute the values
Hence, the friction force acting on block A=40 N
Answer:
The electric field strength inside the capacitor is 49880.77 N/C.
Explanation:
Given:
Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m
Separation between the plates (d) = 0.407 mm =
Energy stored in the capacitor (U) =
Assuming the medium to be air.
So, permittivity of space (ε) =
Area of the square plates is given as:
Capacitance of the capacitor is given as:
Now, we know that, the energy stored in a parallel plate capacitor is given as:
Rewriting in terms of 'E', we get:
Now, plug in the given values and solve for 'E'. This gives,
Therefore, the electric field strength inside the capacitor is 49880.77 N/C