1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
choli [55]
3 years ago
12

I need help on number 1

Mathematics
2 answers:
ollegr [7]3 years ago
7 0
2.5. is the answer. ..
Mashutka [201]3 years ago
6 0
What you do is divide those two numbers. what is 80 divided by 32? the answer is 2.5
You might be interested in
1. What is the slope between the points (2,-5) and (8,3)? *<br><br> Show work please
hjlf

Answer:

\sf m = \dfrac{4}{3}

Step-by-step explanation:

Given, \sf (x_1, ~ y_1) = (2, -5) and \sf (x_2, ~ y_2) = (8, 3)

The slope formula is, \sf m = \dfrac{y_2 - y_1}{x_2 - x_1}

\sf m = \dfrac{3 - (-5)}{8 - 2}

\sf m = \dfrac{8}{6}

\bf m = \dfrac{4}{3}

6 0
2 years ago
12. 4(2x - 8) = 3(2 – 3x)<br> Need help to solve it in steps
Reil [10]
8x - 32 = 6 - 9x
17x = 38
x = 38/17
4 0
3 years ago
A study claims that the combination of vitamin C with vitamin E is more effective for preventing the flu than vitamin C alone. I
victus00 [196]

1) In this study, the control group is the first group of 310 subjects that were instructed to take only 600 mg daily of vitamin C. (Option C; that is, group 1).

2) The study is not Blind (Option C).

In an experimental setup to test a theory, A control group is the set of experimental participants that the theory to be tested isn't applied upon.

In the case of testing a new treatment, the control group is the group that the new treatment isn't administered.

For this question, the experiment was set up to test the effectiveness of a combination of vitamin A and vitamin E in treating flu cases rather than using vitamin C alone. Group A is the only group that only the old treatment alone is applied to; group 1 participants received no dosage of the new combination of treatments to be tested involving vitamins A and E, unlike the two other groups.

It is obvious now why the experimental participants of group 1 are the control group.

2) A blind experiment/study is one in which the participants don't know which group they belong to, whether they are in the control group or the other experimental group. Like in this case, if this was a blind study, the participants wouldn't know which group they belonged to or which treatment is administered to them.

A double-blind experiment/study is one in which both the conductors of the experiment and the participants in the experiment wouldn't know which group any participant is in. The conductors wouldn't know which participants were in the control or treatment group and the participants too wouldn't have an idea whether they are in the control or treatment group.

To learn more about the vitamin visit: brainly.com/question/24324739

#SPJ4

3 0
1 year ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
3 years ago
23 x 32 is the prime factorization for which one of these choices?
antoniya [11.8K]
<h2><u>Answer:</u></h2>

⟶ 2³ × 3² is the prime factorization for which one of these choices?

Let's check,

1) 6 = 3 × 2 [So, obviously not this choice]

2) 25 = 5 × 5 = 5² [Not this either]

3) 36 = 3 × 2 × 2 × 3 = 3² × 2² [Doesn't match with 2³ × 3²]

4) 72 = 2 × 2 × 2 × 3 × 3 = <u>2</u><u>³</u><u> </u><u>×</u><u> </u><u>3</u><u>²</u><u> </u>[Matches]

⟶ The answer is, choice <u>7</u><u>2</u><u>.</u>

\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}

3 0
2 years ago
Other questions:
  • Find the angle of the sector indicated. Find the correct answer to the problem.
    12·2 answers
  • Which of the following is a factor of 2x4 + 22x3 + 60x2?
    10·2 answers
  • The ratio of the current ages of two RSM summer camp students Dylan and Mike is 3:4. If Dylan had been 6 years younger and Mike
    9·1 answer
  • How do I evaluate (9+2) to the power of 2 minus 9 times 3? Does anyone know?
    9·2 answers
  • Help plz what is the answer
    8·1 answer
  • Why is 1/2 and 1/3 similar? Thank you!
    15·1 answer
  • What is the volume of the prism​
    5·1 answer
  • Write an equation of the line passing through point (3, -1) and perpendicular to y= -x+1​
    10·1 answer
  • Help please with my geometry
    7·1 answer
  • Madison is designing a new board game, and is trying to figure out all the possible outcomes. How many different possible outcom
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!