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Aneli [31]
3 years ago
6

Quadratic equation has 5x+0 as a linear factor what value is a zero of the associated quadratic function.

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

9514 1404 393

Answer:

  x = 0

Step-by-step explanation:

The zero is the value of x that makes the linear factor zero:

  5x +0 = 0

  5x = 0 . . . . . simplify

  x = 0/5 = 0 . . . . divide by 5

The associated zero is x = 0.

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Find the solutions to y = (x – 1)2 for x = –3, 0, and 3.
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Answer:

if the 2 is the power of (x-1) here is ur answer

y = (x - 1 ){}^{2} \\if \: x \: is \: \: equal \: to \:  - 3  \\ y =(  - 3 - 1) {}^{2} \\  y = ( - 4) {}^{2} \\ y = 16

if \: x = 0 \\ y = (0 - 1) {}^{2}  \\y = (  - 1) { }^{2} \\ y = 1

if \: x = 3 \\ y = (3 - 1) {}^{2}  \\  y = 2 { }^{2}  \\ y = 4

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3 years ago
Please help me!! I’m bad at math!!
tatyana61 [14]

Answer:

50.24

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And, you're not bad at math! You goot this correct! :)

Step-by-step explanation:

c=25.12

we can use this to find the raidus!

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plug it back into the circumference formula first.

c=(pi)(d)

25.12=3.14*d

divide both sides by 3.14!

d=8 but we need the radius, so we just divide by 2. 8/2 = 4. so the raidus is 4!

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now we plug it into the area of a circle formula.

π · r2

3.14 * 4^2

3.14*16

50.24

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Answer:


Step-by-step explanation:

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