To round 389,422 to the ten thousand, you need to go to the second number which is 8 and round it to the right. To the right of 8 is 9 so if a number is more than 5 you round 8 to 9. Then all the numbers after 8 turn into zeros
So... your answer is:
390,000
Hope I helped! ♥
Answer:
Ans A). The graph is shown.
Ans B). 18.3333 C temperature when F is 65 temperature
Ans C). 32 F when the line crosses the horizontal axis
Ans D). Slope of line C=
is 
Step-by-step explanation:
Given equation is C=
Ans A).
For the table,
Take the four value of F as 32,41,50,59.
For F = 32.
The value of C is
C=
C=
C=0.
For F = 41.
The value of C is
C=
C=
C=05
For F = 50.
The value of C is
C=
C=
C=10
For F = 59.
The value of C is
C=
C=
C=15
<em>Note: The figure shows a graph of given equation with points.</em>
Ans B). Estimate temperature in C when the temperature in F is 65
For F = 65.
The value of C is
C=
C=
<em>C=18.333333.</em>
Ans C). At what temperature, graph lien cross the horizontal axis
When the line crosses the horizontal axis, C=0
Therefore,
C=
0=
0=
F=32 Temperature.
Ans D). Slope of the line C=
The slope of line is given by s= 
Take points from the table of answer A.
let (32,0) and (41,5) using for slope.
s= 
s= 
s= 
Slope of line C=
is 
Answer:
I think its a cute angle im not sure
7.95*0.06 to get amount of tax you're paying
$0.477is how much tax you're paying. (round it up to 0.48)
7.95-0.48
$7.47
The answer is $7.47
Answer:
a) 18
b) 2.101
Step-by-step explanation:
a) What are the degrees of freedom for Student's t distribution when the sample size is 19?
Degrees of freedom = n - 1
Where n = sample size
= 19 - 1
= 18
b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.
(Round your answer to three decimal places.)
We would be determining these using the t distribution table
1 - 0.95 = 0.05 ( for two tailed)
Or
0.05/2 = 0.025(one - tailed)
Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101