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2 years ago

Quadratic equation has 5x+0 as a linear factor what value is a zero of the associated quadratic function.

Mathematics

1 answer:

natka813 [3]2 years ago

7 0

9514 1404 393

Answer:

x = 0

Step-by-step explanation:

The zero is the value of x that makes the linear factor zero:

5x +0 = 0

5x = 0 . . . . . simplify

x = 0/5 = 0 . . . . divide by 5

The associated zero is x = 0.

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Round 389,422 to the ten thousand

frosja888 [35]

To round 389,422 to the ten thousand, you need to go to the second number which is 8 and round it to the right. To the right of 8 is 9 so if a number is more than 5 you round 8 to 9. Then all the numbers after 8 turn into zeros

So... your answer is:

390,000

Hope I helped! ♥

7 0

2 years ago

Read 2 more answers

Does anyone understand this?. I also have to show my work.

snow_lady [41]

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C= $\frac{5}{9}(F -32)$ is $\frac{5}{9}$

Step-by-step explanation:

Given equation is C= $\frac{5}{9}(F -32)$

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=0.

For F = 41.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(41 -32)$

C=05

For F = 50.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(50 -32)$

C=10

For F = 59.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=15

Note: The figure shows a graph of given equation with points.

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=18.333333.

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C= $\frac{5}{9}(F -32)$

0= $\frac{5}{9}(F -32)$

0= $(F -32)$

F=32 Temperature.

Ans D). Slope of the line C= $\frac{5}{9}(F -32)$

The slope of line is given by s= $\frac{Y1-Y2}{X1-X2}$

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= $\frac{Y1-Y2}{X1-X2}$

s= $\frac{0-5}{32-41}$

s= $\frac{5}{9}$

Slope of line C= $\frac{5}{9}(F -32)$ is $\frac{5}{9}$

7 0

3 years ago

IT IS A ANGLE QUESTION PLS HELP

gogolik [260]

Answer:

I think its a cute angle im not sure

6 0

2 years ago

Anton bought a picnic cooler. his total bill with tax was 7.95. he paid 6% sales tax how much did he pay for the cooler alone wi

BabaBlast [244]

7.95*0.06 to get amount of tax you're paying
$0.477is how much tax you're paying. (round it up to 0.48)
7.95-0.48
$7.47
The answer is $7.47

8 0

2 years ago

What are the degrees of freedom for Student's t distribution when the sample size is 19? d.F. = Use the Student's t distribution

liq [111]

Answer:

a) 18

b) 2.101

Step-by-step explanation:

a) What are the degrees of freedom for Student's t distribution when the sample size is 19?

Degrees of freedom = n - 1

Where n = sample size

= 19 - 1

= 18

b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.

(Round your answer to three decimal places.)

We would be determining these using the t distribution table

1 - 0.95 = 0.05 ( for two tailed)

0.05/2 = 0.025(one - tailed)

Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101

7 0

3 years ago