Answer:
The expression that represents the given sequence is 5+6(n-1). Option C (not labeled).
Explanation:
<u>Arithmetic Sequences</u>
In an arithmetic sequence, each term can be obtained by adding or subtracting a fixed number to the previous term. That fixed number is called the common difference.
We are given the following sequence:
5, 11, 17, 23, 29, ...
Each term is located in a position starting from n=1. Let's test each option:
A For n=1 we should have the first term (5). Substituting n=1 into the general equation: 5+6(n+1) = 5+6(1+1) = 5+12 = 17. Since the resulting term is not 5, this option is incorrect.
B For n=1, 6+5(n+1)= 6+5(2)=16. This option is incorrect.
C (not labeled) For n=1, 5+6(n-1)=5+6(1-1)=5+0=5. The first term is correct. Let's test for the second term (n=2):
5+6(2-1)=5+6=11. Correct. For n=3
5+6(3-1)=5+12=17. Correct.
We can see the terms are increasing by 6, and the given sequence is also increasing by 6. Thus, This option is correct.
D For n=1, 6+5 (n-1)=6+0=6. This option is incorrect.
Since <span>each number is the previous number divided by 2, the common ratio 1/2. The common ratio can be solved by dividing the number by the previous number. </span>
The ratio between 28,000 and 14 is 2000 : 1
<h3>How to determine the ratio?</h3>
The numbers are given as:
28,000 and 14
Express as ratio
Ratio = 28000 : 14
Divide each number by 14
Ratio = 2000 : 1
Hence, the ratio between 28,000 and 14 is 2000 : 1
Read more about ratio at:
brainly.com/question/2328454
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1: is A or C 2: A 3: D 4:C Hope this helped
Answer:
I'm getting
y=-7x+8
The 7 is negative for me..You should maybe try yourself too and see what you get I might have made a mistake
Step-by-step explanation:
I'm guessing you live somewhere in the U.S. so I'll use the equation you use there
Equation:


first pick two points
I'll pick (0,8) and (1,1)

this means that the slope is -7
So far the equation will look like this

to get b pick one point, I'll pick (0,8) and replace y and x

when you solve this you'll get b

So the equation will look this
