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horsena [70]
3 years ago
11

Determine whether the results appear to have statistical​ significance, and also determine whether the results appear to have pr

actical significance.In a study of a gender selection method used to increase the likelihood of a baby being born a​ girl, 1971 users of the method gave birth to 965 boys and 1006 girls. There is about an 18​% chance of getting that many girls if the method had no effect.
Because there is a 18% chance of getting that many girls by?
A) has statistical significance
B) does not have statistical significance
C) has practical significance
D) does not have practical significance.
Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

(B) does not have statistical significance

Step-by-step explanation:

given data

gave birth = 1971

boys = 965

girls = 1006

solution

we know here that there is a 18% chance of getting that many girls by chance

as  method it is (B) does not have statistical significance

because here By this method

Percentage of girls is = \frac{1006}{1971}

percentage = 51.04 %

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Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
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<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

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Length of side opposite to θ = 6

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=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

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Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

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=> \frac{x}{12} = 0.73135......

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5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

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Length of side opposite to θ = 12

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8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

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