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Vsevolod [243]
3 years ago
8

The area A of a circle with radius r is given by the function A(r)= pie r^2. Explain what A(3) represents

Mathematics
2 answers:
maksim [4K]3 years ago
3 0

Hello!

A(r) is a function. It takes a value of r, and from that calculates the value A. In this case, it takes the value of a radius, and <u>depending on what that value is</u>, it calculates the area.

A(3) would therefore represent the area based off of a radius of 3.

Hope this helps!

almond37 [142]3 years ago
3 0

Answer:

A(3) = pi (3)^2.

Step-by-step explanation:

A(3) represents the area of a circle with a radius of 3.

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The roots of the equation are 7 and -4, because 7 - 4 = 3 and 7. - 4 = -28

Step-by-step explanation:

The positive number is equal to 7.

Assuming that the number is equal to "x" we have:

\begin{gathered}x^2 = 3x + 28\\\\x^2 - 3x - 28 = 0\\\\a = 1\\\\b = -3\\\\c = -28\\\end{gathered}

By the sum and product method, we have:

\begin{gathered}S = -b / a\\\\S = -(-3) / 1\\\\S = 3\\\\\end{gathered}

\begin{gathered}P= c / a\\\\P = 28 / 1\\\\P = 28\\\\\end{gathered}

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Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t
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Answer:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0:  proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha:  proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1=  6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

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3 years ago
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