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Alika [10]
3 years ago
6

There are 152 steps between the ground floor and the sixth floor in a building. Each step is 16.2 cm tall. It takes 3 minutes an

d 35 seconds for a person with a mass of 59.5 kg to walk all the way up. How much work did the person do?
Physics
1 answer:
lisabon 2012 [21]3 years ago
7 0

Answer:

14.4kJ

Explanation:

Work = Force x distance

W × h = mgh

Given that,

mass m, = 59.5kg

acceleration due to gravity = 9.8m/s^2

height ,h = 16.2cm

convert to m is 0.162m

How much work = m x g x h

height is 0.162 x 152 steps

h = 24.624m

work = 59.5 x 9.8 x 24.624

= 14,358.25Joule

= 14.4kJ

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5. 3 women push a stalled car. Each woman pushes with a 400N force. What is the mass of the car if the car accelerates at 0.85 m
iris [78.8K]

Answer:

<h2>470.59 kg</h2>

Explanation:

The the mass of the car can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{400}{0.85}  \\  = 470.58823...

We have the final answer as

<h3>470.59 kg</h3>

Hope this helps you

7 0
3 years ago
Can someone answer this question quickly??
masya89 [10]

Answer:

Lithium and Sodium

Explanation:

Lithium and Sodium is in the same group 1A

7 0
3 years ago
Two long, straight wires are parallel and 26 cm apart.
mezya [45]

Answer: 2.49×10^-3 N/m

Explanation: The force per unit length that two wires exerts on each other is defined by the formula below

F/L = (u×i1×i2) / (2πr)

Where F/L = force per meter

u = permeability of free space = 1.256×10^-6 mkg/s^2A^2

i1 = current on first wire = 57A

i2 = current on second wire = 57 A

r = distance between both wires = 26cm = 0.26m

By substituting the parameters, we have that

Force per meter = (1.256×10^-6×57×57)/ 2×3.142 ×0.26

= 4080.744×10^-6/ 1.634

= 4.080×10^-3 / 1.634

= 2.49×10^-3 N/m

5 0
3 years ago
PLEASE HELP ME
vichka [17]
Go with the last one because you need potential energy for kinetic energy
8 0
3 years ago
Read 2 more answers
4. The 50-kg crate shown in Fig. rests on a horizontal surface for which the coefficient of
laila [671]

Answer:

5.057 m/s^2

Explanation:

Force of kinetic friction = .3  = F /normal force

  .3 = F /(50* 9.81)     F of friction = 147.15

Net force =   400 - 147.5  =  252.85  N

F = m * a

252.85 = 50 * a       a = 5.057 m/s^2

5 0
2 years ago
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