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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
Balenced
Think of it this way if 2 same weight and same speed objects were racing toward each other perfectly straight then their forces will cancel out and the movement afterwords will be 0
Answer:
14 × a^3
Explanation:
Product means multiplication
Cubed means to the power of 3
Answer:
<u>We are given:</u>
initial velocity (u) = 20m/s
acceleration (a) = 4 m/s²
time (t) = 8 seconds
displacement (s) = s m
<u />
<u>Solving for Displacement:</u>
From the seconds equation of motion:
s = ut + 1/2 * at²
replacing the variables
s = 20(8) + 1/2 * (4)*(8)*(8)
s = 160 + 128
s = 288 m
Answer:
<h3>The answer is 2.15 m/s²</h3>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
where
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>2.15 m/s²</h3>
Hope this helps you
